Submission #7766

#	Time	Username	Problem	Language	Result	Execution time	Memory
7766		studenttest	생일수 II (GA4_birthday2)	C++98	45 / 100	1000 ms	3040 KiB

birthday2

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
char a[200001], b[200001];
int x[200001], y[200001];
int main()
{
    long long int i, kx, ky, k, kk, c=0, z, ans=0;
    scanf("%s", a);
    scanf("%s", b);
    kx = strlen(a);
    ky = strlen(b);
    for(i=1;i<=kx;i++){
        if(a[kx-i]=='3') x[i] = 3;
        if(a[kx-i]=='5') x[i] = 5;
        if(a[kx-i]=='8') x[i] = 8;
    }
    for(i=1;i<=ky;i++){
        if(b[ky-i]=='3') y[i] = 3;
        if(b[ky-i]=='5') y[i] = 5;
        if(b[ky-i]=='8') y[i] = 8;
    }
    k = 0;
    if(kx>8){
        for(i=kx;i>kx-8;i--){
            k*=10;
            k+=x[i];
        }
        k%=19980305;
        for(i=kx-8;i>=1;i--){
            k*=10;
            k+=x[i];
            k%=19980305;
        }
    }
    else{
        for(i=kx;i>=1;i--){
            k*=10;
            k+=x[i];
        }
    }
    while(1){
        if(x[1]==3){
            x[1] = 5;
            kk = k+2;
        }
        else if(x[1]==5){
            x[1] = 8;
            kk = k+3;
        }
        else{
            x[1] = 3;
            for(i=2;i<=kx+1;i++){
                if(i==kx+1){
                    kx++;
                    x[i] = 3;
                    break;
                }
                if(x[i]==3){
                    x[i] = 5;
                    break;
                }
                else if(x[i]==5){
                    x[i] = 8;
                    break;
                }
                else{
                    x[i] = 3;
                }
            }
            kk = 0;
            if(kx>8){
                for(i=kx;i>kx-8;i--){
                    kk*=10;
                    kk+=x[i];
                }
                kk%=19980305;
                for(i=kx-8;i>=1;i--){
                    kk*=10;
                    kk+=x[i];
                    kk%=19980305;
                }
            }
            else{
                for(i=kx;i>=1;i--){
                    kk*=10;
                    kk+=x[i];
                }
            }
        }
        z = 0;
        for(i=1;i<=ky;i++){
            if(x[i]!=y[i]){
                z = 1;
                break;
            }
        }
        ans = (ans+(k*kk))%19980305;
        if(z==0) break;
        k = kk;
    }
    printf("%lld", ans);
    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 15 / 15
• Subtask 3: 20 / 20
• Subtask 4: 0 / 25
• Subtask 5: 0 / 30