Submission #776247

#	Time	Username	Problem	Language	Result	Execution time	Memory
776247		Alan	Cyberland (APIO23_cyberland)	C++17	100 / 100	2286 ms	92632 KiB

cyberland

#include "cyberland.h"
#include <bits/stdc++.h>
using namespace std;
#define int long long
 
const double INF = 1E18;
 
struct node {
    double di;
    int u, k;
    bool operator > (const node& o) const {
        if (k != o.k) return k > o.k;
        return di > o.di;
    }
};
 
double solve(int32_t N, int32_t M, int32_t K, int32_t H, std::vector<int32_t> x, std::vector<int32_t> y, std::vector<int32_t> c, std::vector<int32_t> arr) {
    K = min(K, 120);
    vector<pair<int, int>> adj[N];
    vector<vector<double>> d(N, vector<double> (K + 1, INF));
    for (int i = 0; i < M; i++) {
        if (x[i] != H) adj[x[i]].push_back({y[i], c[i]});
        if (y[i] != H) adj[y[i]].push_back({x[i], c[i]});
    }
    queue<int> q;
    vector<bool> vis(N, 0);
    vis[0] = 1;
    q.push(0);
    while (!q.empty()) {
        int u = q.front();
        q.pop();
        for (auto& [v, w] : adj[u]) {
            if (!vis[v]) {
                vis[v] = true;
                q.push(v);
            }
        }
    }
    using T = node;
    priority_queue<T, vector<T>, greater<T>> pq;
    pq.push({0.0, 0, 0});
    d[0][0] = 0.0;
    for (int i = 0; i < N; i++) if (arr[i] == 0 && vis[i]) {
        pq.push({0.0, i, 0});
        d[i][0] = 0.0;
    }
    while (!pq.empty()) {
        auto [di, u, k] = pq.top();
        pq.pop();
        if (di != d[u][k]) continue;
        for (auto& [v, w] : adj[u]) {
            double new_weight = d[u][k] + w;
            if (d[v][k] > new_weight) {
                d[v][k] = new_weight;
                pq.push((node) {d[v][k], v, k});
            }
            if (arr[v] == 2 && k != K) {
                double new_weight = d[u][k] + w;
                new_weight /= 2.0;
                if (d[v][k + 1] > new_weight) {
                    d[v][k + 1] = new_weight;
                    pq.push((node) {d[v][k + 1], v, k + 1});
                }
            }
        }
    }
    double res = *min_element(d[H].begin(), d[H].end());
    if (res >= INF) return -1;
    return res;
}

• Subtask 1: 5 / 5
• Subtask 2: 8 / 8
• Subtask 3: 13 / 13
• Subtask 4: 19 / 19
• Subtask 5: 7 / 7
• Subtask 6: 16 / 16
• Subtask 7: 29 / 29
• Subtask 8: 3 / 3