Submission #774970

#TimeUsernameProblemLanguageResultExecution timeMemory
774970vjudge1Addk (eJOI21_addk)C++17
0 / 100
24 ms1900 KiB
//#pragma GCC optimize("Ofast,unroll-loops") //#pragma GCC target("bmi,bmi2,lzcnt,popcnt") //#pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native") //#pragma expected_value //#pragma isolated_call //#pragma disjoint #include<bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> //using namespace __gnu_pbds; using namespace std; #define int long long //#define double long double #define Fi first #define Se second #define Rep(i,a,b) for (int i=a;i<=b;++i) #define Repu(i,b,a) for (int i=b;i>=a;--i) #define pb push_back #define ms(a,i) memset(a,i,sizeof(a)) #define sz size() #define mp make_pair #define endl '\n' #define sef setprecision(6)<<fixed #define cer cout<<"cak"<<endl; typedef pair<int,int> ii; typedef vector<int> vi; typedef vector<double> va; typedef vector<ii> vii; typedef vector<vi> vvi; typedef vector<va> vva; //const double EPS=1e-9; const double PI=acos(-1); const long long oo=1e18; const int MN=1e6+5; const int mod=1e9+7; using cd=complex<double>; //typedef tree<int,null_type,less<int>,rb_tree_tag, tree_order_statistics_node_update> index_set; int n,k,q; int a[MN]; int pre[MN]; int sum[MN]; int doi[15]; int calc1(int l,int r) { if(l>r) return 0; return pre[r] - pre[l-1] - (l-1)*(sum[r]-sum[l-1]); } int calc2(int l,int r) { if(l>r) return 0; return (r+1)*(sum[r]-sum[l-1]) - (pre[r]-pre[l-1]); } int calc3(int l,int r) { if(l>r) return 0; return sum[r] - sum[l-1]; } signed main() { //freopen(".inp","r",stdin); freopen(".out","w",stdout); ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cin>>n>>k; Rep(i,1,n) cin>>a[i]; Rep(i,1,n) { pre[i] = pre[i-1] + i*a[i]; sum[i] = sum[i-1] + a[i]; } cin>>q; while(q--) { int type; cin>>type; if(type==1) { Rep(i,1,k) cin>>doi[i]; } else { int l,r,m; cin>>l>>r>>m; int dr=min((l+r)/2,l+m-2); int tl=max((l+r+1)/2,r-m+2); if(dr==tl) tl++; int sum = calc1(l,dr) + calc2(tl,r) + calc3(tl+1,dr-1)*m; cout<<sum<<endl; } } }
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