Submission #774409

#TimeUsernameProblemLanguageResultExecution timeMemory
774409OrazBBali Sculptures (APIO15_sculpture)C++17
0 / 100
1 ms328 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <functional> using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; //Dijkstra->set //set.find_by_order(x) x-position value //set.order_of_key(x) number of strictly less elements don't need *set.?? #define N 100005 #define wr cout << "Continue debugging\n"; #define all(x) (x).begin(), (x).end() #define ll long long int #define pii pair <int, int> #define pb push_back #define ff first #define ss second const ll inf = 1e18; int a[N]; ll pref[N]; int main () { ios::sync_with_stdio(false); cin.tie(0); int n, A, B; cin >> n >> A >> B; for (int i = 1; i <= n; i++){ cin >> a[i]; pref[i] = pref[i-1]+a[i]; } vector<vector<ll>> dp(n+1, vector<ll>(n+1, inf)); dp[1][1] = a[1]; for (int i = 2; i <= n; i++){ dp[i][1] = dp[i-1][1]+a[i]; } for (int j = 2; j <= B; j++){ for (int i = j; i <= n; i++){ ll sum = 0; for (int k = i; k >= j; k--){ sum += a[k]; dp[i][j] = min(dp[i][j], sum|dp[k-1][j-1]); } } } ll mn = inf; for (int i = A; i <= B; i++) mn = min(mn, dp[n][i]); cout << mn << '\n'; }
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