Submission #773032

#	Time	Username	Problem	Language	Result	Execution time	Memory
773032		Valters07	Abracadabra (CEOI22_abracadabra)	C++14	0 / 100	3 ms	4948 KiB

Main

#include <bits/stdc++.h>
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,popcnt,lzcnt")
#define fio ios_base::sync_with_stdio(0);cin.tie(0);
#define ll long long
#define en cin.close();return 0;
#define pb push_back
#define fi first//printf("%lli\n",cur);
#define se second//scanf("%lli",&n);
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int N = 2e5+5;
struct node
{
    int prior, val, mx, sz, l, r;
};
vector<node> treap;
vector<pair<int,int> > qu[N];
int nw(int val)
{
    treap.pb({rand(),val,val,1,0,0});
    return treap.size()-1;
}
int merg(int t1, int t2)
{
    if(t1==0||t2==0)
        return (t1|t2);
    if(treap[t1].prior<treap[t2].prior)
    {
        treap[t1].r=merg(treap[t1].r,t2);
        treap[t1].mx=max({treap[t1].val,treap[treap[t1].l].mx,treap[treap[t1].r].mx});
        treap[t1].sz=treap[treap[t1].l].sz+treap[treap[t1].r].sz+1;
        return t1;
    }
    else
    {
        treap[t2].l=merg(t1,treap[t2].l);
        treap[t2].mx=max({treap[t2].val,treap[treap[t2].l].mx,treap[treap[t2].r].mx});
        treap[t2].sz=treap[treap[t2].l].sz+treap[treap[t2].r].sz+1;
        return t2;
    }
}
pair<int,int> splitbysize(int t, int sz)
{
    if(treap[t].sz==sz)
        return {t,0};
    int l = treap[t].l, r = treap[t].r;
//    cout << t << " : " << l << " " << r << "  " << sz << endl;
    if(treap[l].sz>sz)
    {
        pair<int,int> tt = splitbysize(l,sz);
        treap[t].l=tt.se;
        treap[t].mx=max({treap[t].val,treap[treap[t].l].mx,treap[treap[t].r].mx});
        treap[t].sz=treap[treap[t].l].sz+treap[treap[t].r].sz+1;
        return {tt.fi,t};
    }
    else
    {
        pair<int,int> tt = splitbysize(r,sz-treap[l].sz);
        treap[t].r=tt.fi;
        treap[t].mx=max({treap[t].val,treap[treap[t].l].mx,treap[treap[t].r].mx});
        treap[t].sz=treap[treap[t].l].sz+treap[treap[t].r].sz+1;
        return {t,tt.se};
    }
}
pair<int,int> splitbymax(int t, int val)
{
    if(treap[t].mx<=val)
        return {t,0};
    int l = treap[t].l, r = treap[t].r;
    if(treap[l].mx>val)
    {
        pair<int,int> tt = splitbymax(l,val);
        treap[t].l=tt.se;
        treap[t].mx=max({treap[t].val,treap[treap[t].l].mx,treap[treap[t].r].mx});
        treap[t].sz=treap[treap[t].l].sz+treap[treap[t].r].sz+1;
        return {tt.fi,t};
    }
    else
    {
        pair<int,int> tt = splitbymax(r,val);
        treap[t].r=tt.fi;
        treap[t].mx=max({treap[t].val,treap[treap[t].l].mx,treap[treap[t].r].mx});
        treap[t].sz=treap[treap[t].l].sz+treap[treap[t].r].sz+1;
        return {t,tt.se};
    }
}
vector<int> make_op(vector<int> &a)
{
    int n = a.size();
    vector<int> ret;
    int it = 0, it2 = n/2;
    while(it<n/2||it2<n)
    {
        if(it==n/2)
            ret.pb(a[it2++]);
        else if(it2==n)
            ret.pb(a[it++]);
        else if(a[it]<a[it2])
            ret.pb(a[it++]);
        else
            ret.pb(a[it2++]);
    }
    return ret;
}
int main()
{
    fio
    ifstream cin("in.in");
    srand(6954);
    treap.pb({0,0,0,0,0,0});
    int n, q, r = 1;
    cin >> n >> q;
    vector<int> a(n), ans(q);
    for(auto &x:a)
        cin >> x;
    for(int qi = 0;qi<q;qi++)
    {
        int t, x;
        cin >> t >> x;
        qu[min(t,N-1)].pb({x,qi});
    }
    for(int i = 0;i<N;i++)
    {
        if(i==0)
        {
            for(auto x:qu[i])
                ans[x.se]=a[x.fi-1];
            a=make_op(a);
            for(int i = 0;i<n;i++)
                r=merg(r,nw(a[i]));
        }
        else
        {
            for(auto x:qu[i])
            {
                auto t = splitbysize(r,x.fi);
                cout << t.fi << " " << treap[t.fi].l;en
                cout << treap[treap[t.fi].l].val << " " << t.se;en
                auto t2 = splitbysize(t.fi,x.fi-1);
                ans[x.se]=treap[t2.se].val;
                r=merg(t2.fi,merg(t2.se,t.se));
            }
            auto t = splitbysize(r,n/2);
            while(treap[t.se].sz>1)
            {
                auto t1 = splitbysize(t.se,1);
                int val = treap[t1.fi].val;
                auto t2 = splitbymax(merg(t1.fi,t1.se),val);
                auto t3 = splitbymax(t.fi,val);
                t.fi=merg(merg(t3.fi,t2.fi),t3.se);
                t.se=t2.se;
            }
            r=merg(t.fi,t.se);
        }
    }
    for(auto x:ans)
        cout << x << "\n";
    cin.close();
    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 40
• Subtask 3: 0 / 25
• Subtask 4: 0 / 25