Submission #772740

#	Time	Username	Problem	Language	Result	Execution time	Memory
772740		lollipop	Last supper (IOI12_supper)	C++17	0 / 100	307 ms	22032 KiB

advisor

#include "advisor.h"
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
//#define int long long
#define pb push_back
#define s second
#define f first
#define pf push_front
#define inf 100000000000000000
#define bitebi __builtin_popcountll
#define FOR( i , n ) for( int i = 0 ; i < n ; i ++ )
#define YES cout <<"YES\n"
#define NO cout << "NO\n"
#define debug cout << "Here Fine" << endl ;
#define pr pair < int , int >
#define fbo find_by_order // returns iterator
#define ook order_of_key // returns strictly less numbers than key
using namespace std ;
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,fma")
using namespace __gnu_pbds;
using namespace __gnu_cxx;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
const double Pi=acos(-1.0);
const double EPS=1E-8;
const int mod =  1000000007 ;
const int mod1 = 998244353 ;
const int N = 2e5 + 10 ;
mt19937 R(time(0));
map < int , int > ma , ma1 ;
vector < int > v[ N ] ;
int xx[ 30 ] , cur[ N ] ;
void ComputeAdvice(int *c, int n, int r, int m){
	 for( int j = n - 1 ; j >= 0 ; j -- ){
	 	v[ c[ j ] ].pb( j ) ;
	 }
	 int cs = 15 ;
	 if( r > 25000 ) cs = 18 ; 
	 xx[ 0 ] = 1 ; 
	 for( int i = 1 ; i <= 19 ; i ++ ) xx[ i ] = xx[ i - 1 ] * 2 ;
	 FOR( i , n ) cur[ i ] = -1 ; 
	 FOR( i , r ) cur[ i ] = i ;
	 set < pair < int , int > > se ; 
	 FOR( i , r ){
	 	int pos = INT_MAX ; 
		if( v[ i ].size() != 0 ) pos = v[ i ][ v[ i ].size() - 1 ] ;
		pair < int , int > p ; 
		p.f = pos ; p.s = i ; 
		se.insert( p ) ;
	 }
	 FOR( i , n ){
	 	int x = c[ i ] ; 
	 	if( cur[ x ] != -1 ){
	 	int pos = INT_MAX ; 
		if( v[ x ].size() != 0 ) pos = v[ x ][ v[ x ].size() - 1 ] ;
		pair < int , int > p ; 
		p.f = pos ; p.s = x ; 
		se.erase( se.find( p ) ) ;
	 		v[ x ].pop_back() ;
	    pos = INT_MAX ; 
		if( v[ x ].size() != 0 ) pos = v[ x ][ v[ x ].size() - 1 ] ;
		p.f = pos ; p.s = x ; 
		se.insert( p ) ;
	 		FOR( j , cs ) WriteAdvice( 0 ) ;
	 		continue ; 
		}
		pair < int , int > p ;
		p = *(--se.end() ) ;
		se.erase( --se.end() ) ; 
		v[ x ].pop_back() ;
 	 	int pos = INT_MAX ; 
		if( v[ x ].size() != 0 ) pos = v[ x ][ v[ x ].size() - 1 ] ;
		pair < int , int > p1 ; 
		p1.f = pos ; p1.s = x ; 
		se.insert( p1 ) ;
		
		cur[ x ] = cur[ p.s ] ; 
		int ps = cur[ p.s ] ; 
		cur[ p.s ] = -1 ; 
		FOR( j , cs ){
			int y = ( ps & xx[ j ] ) ;
			if( y == 0 ) WriteAdvice( 0 ) ;
			else WriteAdvice( 1 ) ;
		}		 
	 } 
}

//void WriteAdvice(unsigned char a);

assistant

#include "assistant.h"
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
//#define int long long
#define pb push_back
#define s second
#define f first
#define pf push_front
#define inf 100000000000000000
#define bitebi __builtin_popcountll
#define FOR( i , n ) for( int i = 0 ; i < n ; i ++ )
#define YES cout <<"YES\n"
#define NO cout << "NO\n"
#define debug cout << "Here Fine" << endl ;
#define pr pair < int , int >
#define fbo find_by_order // returns iterator
#define ook order_of_key // returns strictly less numbers than key
using namespace std ;
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,fma")
using namespace __gnu_pbds;
using namespace __gnu_cxx;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
const double Pi=acos(-1.0);
const double EPS=1E-8;
const int mod =  1000000007 ;
const int mod1 = 998244353 ;
const int N = 2e5 + 10 ;
mt19937 R(time(0));
map < int , int > ma , ma1 ;
int xx[ 30 ] , cur[ N ] , invcur[ N ] ; 
void Assist(unsigned char *a, int n, int r, int rr){
	 int cs = 15 ;
	 if( r > 25000 ) cs = 18 ; 
	 xx[ 0 ] = 1 ; 
	 for( int i = 1 ; i <= 19 ; i ++ ) xx[ i ] = xx[ i - 1 ] * 2 ;
	 FOR( i , n ) cur[ i ] = -1 ; 
	 FOR( i , r ) cur[ i ] = i , invcur[ i ] = i ;
	 int pos = 0 ;
	 FOR( i , N ){
	 	int x = GetRequest(); 
	 	if( cur[ x ] != -1 ){
	 	    pos += cs ; continue ;	
		}
		int nmb = 0 ;
		FOR( j , cs ){
			if( a[ pos ] == 1 ) nmb += xx[ j ] ;  
		    pos ++ ; 
		}
		PutBack( invcur[ nmb ] ) ; 
		cur[ invcur[ nmb ] ] = -1 ; 
		invcur[ nmb ] = x ;
		cur[ x ] = nmb ;  
	 }
}

//void PutBack(int T);
//
//int GetRequest();

• Subtask 1: 0 / 8
• Subtask 2: 0 / 9
• Subtask 3: 0 / 9
• Subtask 4: 0 / 35
• Subtask 5: 0 / 39