Submission #771156

#	Time	Username	Problem	Language	Result	Execution time	Memory
771156		bachhoangxuan	Coin Collecting (JOI19_ho_t4)	C++17	100 / 100	38 ms	6476 KiB

joi2019_ho_t4

// Judges with GCC >= 12 only needs Ofast
// #pragma GCC optimize("O3,no-stack-protector,fast-math,unroll-loops,tree-vectorize")
// MLE optimization
// #pragma GCC optimize("conserve-stack")
// Old judges
// #pragma GCC target("sse4.2,popcnt,lzcnt,abm,mmx,fma,bmi,bmi2")
// New judges. Test with assert(__builtin_cpu_supports("avx2"));
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native")
// Atcoder
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma")
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
- insert(x),erase(x)
- find_by_order(k): return iterator to the k-th smallest element
- order_of_key(x): the number of elements that are strictly smaller
*/
#include<bits/stdc++.h>
using namespace std;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
uniform_real_distribution<> pp(0.0,1.0);
#define int long long
#define ld long double
#define pii pair<int,int>
#define piii pair<pii,int>
#define mpp make_pair
#define fi first
#define se second
const int inf=1e18;
const int mod=1e9+7;
const int maxn=100005;
const int bl=650;
const int maxs=655;
const int maxm=200005;
const int maxq=500005;
const int maxl=20;
const int maxa=250000;
const int root=3;
int power(int a,int n){
    int res=1;
    while(n){
        if(n&1) res=res*a%mod;
        a=a*a%mod;n>>=1;
    }
    return res;
}
const int iroot=power(3,mod-2);
const int base=101;
int n,ans,cnt[maxn][2];
void solve(){
    cin >> n;
    for(int i=0;i<2*n;i++){
        int x,y;cin >> x >> y;
        if(x<1) ans+=1-x,x=1;
        if(x>n) ans+=x-n,x=n;
        if(y<1) ans+=1-y,y=1;
        if(y>2) ans+=y-2,y=2;
        cnt[x][y-1]++;
    }
    for(int i=1;i<=n;i++){
        cnt[i][0]+=cnt[i-1][0]-1;
        cnt[i][1]+=cnt[i-1][1]-1;
        for(int j=0;j<2;j++){
            if(cnt[i][j]>0 && cnt[i][j^1]<0){
                int t=min(cnt[i][j],-cnt[i][j^1]);
                ans+=t;cnt[i][j]-=t;cnt[i][j^1]+=t;
            }
        }
        ans+=abs(cnt[i][0])+abs(cnt[i][1]);
    }
    cout << ans << '\n';
}
signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);cout.tie(NULL);
    int test=1;//cin >> test;
    while(test--) solve();
}

• Subtask 1: 8 / 8
• Subtask 2: 29 / 29
• Subtask 3: 63 / 63