Submission #771133

#TimeUsernameProblemLanguageResultExecution timeMemory
771133OrazBBootfall (IZhO17_bootfall)C++17
100 / 100
287 ms3448 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <functional> using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; //Dijkstra->set //set.find_by_order(x) x-position value //set.order_of_key(x) number of strictly less elements don't need *set.?? #define N 100005 #define wr cout << "Continue debugging\n"; #define all(x) (x).begin(), (x).end() #define ll long long int #define pii pair <int, int> #define pb push_back #define ff first #define ss second int main () { ios::sync_with_stdio(false); cin.tie(0); int n; cin >> n; vector<int>a(n+1,0); int S=0; for (int i = 1; i <= n; i++){ cin >> a[i]; S += a[i]; } vector<int> dp(S+1,0), can(S+1,0); dp[0]=1; for (int i = 1; i <= n; i++){ for (int j = S-a[i]; j >= 0; j--){ dp[j+a[i]] += dp[j]; } } if (S%2 or !dp[S/2]) return cout << 0, 0; for (int i = 1; i <= n; i++){ for (int j = a[i]; j <= S; j++){ dp[j] -= dp[j-a[i]]; } int newS = S-a[i]; for (int j = 0; j <= newS/2; j++){ if (dp[j]) can[newS-2*j]++; } for (int j = S-a[i]; j >= 0; j--){ dp[j+a[i]] += dp[j]; } } vector<int> ans; for (int i = 1; i <= S; i++){ if (can[i] == n) ans.pb(i); } cout << ans.size() << '\n'; for (auto i : ans){ cout << i << " "; } }
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