Submission #766202

#TimeUsernameProblemLanguageResultExecution timeMemory
766202SanguineChameleonAliens (IOI16_aliens)C++17
100 / 100
157 ms12716 KiB
#include "aliens.h" #include <bits/stdc++.h> using namespace std; const int maxN = 1e5 + 20; const long long inf = 1e18L + 20; const long long max_cost = 1e12L + 20; pair<int, int> ranges[maxN]; int L[maxN]; int R[maxN]; long long over[maxN]; pair<long long, int> dp[maxN]; int N, K; struct line { long long a, b, cnt; line(): a(0), b(0), cnt(0) {}; line(long long _a, long long _b, int _cnt): a(_a), b(_b), cnt(_cnt) {}; long long eval(int x) { return a * x + b; } }; long long floor_div(long long a, long long b) { return a / b; } long long inter(line L1, line L2) { return floor_div(L2.b - L1.b, L1.a - L2.a); } struct CHT { vector<line> Q; int pt = 0; void add(line L) { while ((int)Q.size() >= 2 && inter(Q.end()[-2], Q.back()) >= inter(Q.back(), L)) { Q.pop_back(); } Q.push_back(L); } line get(int x) { pt = min(pt, (int)Q.size() - 1); while (pt + 1 < (int)Q.size() && Q[pt].eval(x) > Q[pt + 1].eval(x)) { pt++; } return Q[pt]; } }; void calc(long long cost) { CHT C; dp[0] = make_pair(0, 0); C.add(line(-2 * L[1], 1LL * L[1] * L[1] - over[1] + cost, 0)); for (int i = 1; i <= N; i++) { auto best = C.get(R[i]); dp[i].first = best.eval(R[i]) + 1LL * R[i] * R[i]; dp[i].second = best.cnt + 1; if (i == N) { break; } C.add(line(-2 * L[i + 1], dp[i].first + 1LL * L[i + 1] * L[i + 1] - over[i + 1] + cost, dp[i].second)); } } long long take_photos(int _N, int M, int _K, vector<int> row, vector<int> col) { N = _N; K = _K; for (int i = 1; i <= N; i++) { if (row[i - 1] <= col[i - 1]) { ranges[i].first = row[i - 1]; ranges[i].second = -col[i - 1]; } else { ranges[i].first = col[i - 1]; ranges[i].second = -row[i - 1]; } } sort(ranges + 1, ranges + N + 1); int cnt = 0; for (int i = 1; i <= N; i++) { if (cnt == 0 || (L[cnt] != ranges[i].first && -ranges[i].second > R[cnt])) { cnt++; L[cnt] = ranges[i].first - 1; R[cnt] = -ranges[i].second; } } N = cnt; for (int i = 2; i <= N; i++) { if (R[i - 1] > L[i]) { over[i] = 1LL * (R[i - 1] - L[i]) * (R[i - 1] - L[i]); } } K = min(K, N); long long lt = 0; long long rt = max_cost; long long res = inf; while (lt <= rt) { long long mt = (lt + rt) / 2; calc(mt); if (dp[N].second <= K) { res = dp[N].first - mt * K; rt = mt - 1; } else { lt = mt + 1; } } return res; }
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