Submission #765766

#	Time	Username	Problem	Language	Result	Execution time	Memory
765766		SanguineChameleon	Shortcut (IOI16_shortcut)	C++17	23 / 100	2079 ms	560 KiB

shortcut

#include "shortcut.h"
#include <bits/stdc++.h>
using namespace std;

const int maxn = 3e3 + 20;
const long long inf = 1e18L;
long long len[maxn];
int depth[maxn];
int n, c;

long long calc(long long lim) {
	long long res = inf;
	for (int x = 1; x <= n; x++) {
		for (int y = x + 1; y <= n; y++) {
			long long mx = 0;
			for (int i = 1; i <= n; i++) {
				for (int j = i + 1; j <= x; j++) {
					if (len[j] - len[i] + depth[i] + depth[j] > lim) {
						mx = max(mx, inf);
					}
				}
			}
			for (int i = y; i <= n; i++) {
				for (int j = i + 1; j <= n; j++) {
					if (len[j] - len[i] + depth[i] + depth[j] > lim) {
						mx = max(mx, inf);
					}
				}
			}
			for (int i = 1; i <= x; i++) {
				for (int j = x + 1; j <= y; j++) {
					long long d1 = len[y] - len[x] + c - (len[j] - len[x]) + len[x] - len[i] + depth[i] + depth[j];
					long long d2 = len[j] - len[i] + depth[i] + depth[j];
					if (d2 > lim) {
						mx = max(mx, d1);
					}
				}
			}
			for (int i = x; i <= y - 1; i++) {
				for (int j = y; j <= n; j++) {
					long long d1 = len[y] - len[x] + c - (len[y] - len[i]) + len[j] - len[y] + depth[i] + depth[j];
					long long d2 = len[j] - len[i] + depth[i] + depth[j];
					if (d2 > lim) {
						mx = max(mx, d1);
					}
				}
			}
			for (int i = x; i <= y; i++) {
				for (int j = i + 1; j <= y; j++) {
					long long d1 = len[y] - len[x] + c - (len[j] - len[i]) + depth[i] + depth[j];
					long long d2 = len[j] - len[i] + depth[i] + depth[j];
					if (d2 > lim) {
						mx = max(mx, d1);
					}
				}
			}
			for (int i = 1; i <= x; i++) {
				for (int j = y; j <= n; j++) {
					long long d1 = len[j] - len[i] - (len[y] - len[x]) + c + depth[i] + depth[j];
					long long d2 = len[j] - len[i] + depth[i] + depth[j];
					if (d2 > lim) {
						mx = max(mx, d1);
					}
				}
			}
			res = min(res, mx);
		}
	}
	return res;
}

long long dist[maxn * maxn];

long long find_shortcut(int _n, vector<int> _len, vector<int> _depth, int _c) {
	n = _n;
	c = _c;
	len[1] = 0;
	for (int i = 2; i <= n; i++) {
		len[i] = len[i - 1] + _len[i - 2];
	}
	for (int i = 1; i <= n; i++) {
		depth[i] = _depth[i - 1];
	}
	int cnt = 0;
	for (int i = 1; i <= n; i++) {
		for (int j = i + 1; j <= n; j++) {
			dist[cnt++] = len[j] - len[i] + depth[i] + depth[j];
		}
	}
	sort(dist, dist + cnt, greater<>());
	long long res = dist[0];
	int lt = 0;
	int rt = cnt - 1;
	while (lt <= rt) {
		int mt = (lt + rt) / 2;
		long long mx = calc(dist[mt] - 1);
		if (mx < dist[mt]) {
			res = max(mx, dist[mt + 1]);
			lt = mt + 1;
		}
		else {
			rt = mt - 1;
		}
	}
	return res;
}

• Subtask 1: 9 / 9
• Subtask 2: 14 / 14
• Subtask 3: 0 / 8
• Subtask 4: 0 / 7
• Subtask 5: 0 / 33
• Subtask 6: 0 / 22
• Subtask 7: 0 / 4
• Subtask 8: 0 / 3