Submission #765509

#TimeUsernameProblemLanguageResultExecution timeMemory
765509Drew_Crossing (JOI21_crossing)C++17
100 / 100
2013 ms7632 KiB
#include <iostream> #include <set> #include <algorithm> #include <cassert> using namespace std; #define ll long long const int MAX = 2e5 + 69; const int BLOCK = 777; const int prime = 991; const int mod = 1e9 + 9; inline int add(ll x, ll y) { return (int)((x + y) % mod); } inline int sub(ll x, ll y) { return (int)((x - y + mod) % mod); } inline int mul(ll x, ll y) { return (int)((x * y) % mod); } inline int fpow(ll x, ll y) { int res = 1; while (y) { if (y & 1) res = mul(res, x); x = mul(x, x); y >>= 1; } return res; } int n, q; int pwr[MAX], inv[MAX]; int ALLSAME[3]; //0: 'J', 1: 'O', 2: 'I', length: BLOCK int value[MAX / BLOCK + 5]; //hash value for each block char lazy[MAX / BLOCK + 5]; string s[3], t; set<int> flower; inline string combine(const string &a, const string &b) { string res = ""; for (int i = 0; i < n; ++i) { if (a[i] == b[i]) res += a[i]; else if (a[i] != 'J' && b[i] != 'J') res += 'J'; else if (a[i] != 'O' && b[i] != 'O') res += 'O'; else if (a[i] != 'I' && b[i] != 'I') res += 'I'; } if ((int)res.size() != n) cerr << a << " " << b << '\n'; return res; } inline void genFlower() { set<string> st; for (int i = 0; i < 3; ++i) st.insert(s[i]); while (true) { bool ok = true; for (const string &a : st) { for (const string &b : st) { if (!st.count(combine(a, b))) { st.insert(combine(a, b)); ok = false; } } } if (ok) break; } for (const string &x : st) { int sum = 0; for (int i = 0; i < n; ++i) sum = add(sum, mul(x[i], pwr[i])); flower.insert(sum); } return; } inline void update(int l, int r, char c) { int id; if (c == 'J') id = 0; if (c == 'O') id = 1; if (c == 'I') id = 2; int b1 = l / BLOCK, b2 = r / BLOCK; if (b1 == b2) { if (lazy[b1]) { for (int i = b1 * BLOCK; i < min(n, (b1 + 1) * BLOCK); ++i) t[i] = lazy[b1]; lazy[b1] = 0; } for (int i = l; i <= r; ++i) t[i] = c; int sum = 0; for (int i = b1 * BLOCK; i < min(n, (b1 + 1) * BLOCK); ++i) sum = add(sum, mul(t[i], pwr[i - b1 * BLOCK])); value[b1] = sum; } else { update(l, (b1 + 1) * BLOCK - 1, c); update(b2 * BLOCK, r, c); for (int i = b1 + 1; i < b2; ++i) lazy[i] = c, value[i] = ALLSAME[id]; } } inline void out() { int sum = 0; for (int B = 0; B <= (n-1) / BLOCK; ++B) sum = add(sum, mul(value[B], pwr[B * BLOCK])); if (flower.count(sum)) cout << "Yes\n"; else cout << "No\n"; } int main() { ios :: sync_with_stdio(0); cin.tie(0); cout.tie(0); // The number of flower (after cross breeding) is small // Generate all Flower // Maintain current generation (string T) // using blocks, (size of sqrt(N)) // Complexity: O(N + Q sqrt N) pwr[0] = 1; for (int i = 1; i < MAX; ++i) pwr[i] = mul(prime, pwr[i-1]); inv[MAX-1] = fpow(pwr[MAX-1], mod-2); for (int i = MAX-2; i >= 0; --i) inv[i] = mul(prime, inv[i+1]); for (int i = 0; i < 3; ++i) { int sum = 0; for (int j = 0; j < BLOCK; ++j) sum = add(sum, mul("JOI"[i], pwr[j])); ALLSAME[i] = sum; } cin >> n; for (int i = 0; i < 3; ++i) cin >> s[i]; genFlower(); cin >> q >> t; //generating value for (int B = 0; B <= (n-1) / BLOCK; ++B) { int sum = 0; for (int i = B * BLOCK; i < min(n, (B+1) * BLOCK); ++i) sum = add(sum, mul(t[i], pwr[i - B * BLOCK])); value[B] = sum; } out(); while (q--) { int l, r; char c; cin >> l >> r >> c; update(l-1, r-1, c); out(); } return 0; }
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