Submission #760663

#TimeUsernameProblemLanguageResultExecution timeMemory
760663bachhoangxuanSprinkler (JOI22_sprinkler)C++17
100 / 100
1272 ms114704 KiB
// Judges with GCC >= 12 only needs Ofast // #pragma GCC optimize("O3,no-stack-protector,fast-math,unroll-loops,tree-vectorize") // MLE optimization // #pragma GCC optimize("conserve-stack") // Old judges // #pragma GCC target("sse4.2,popcnt,lzcnt,abm,mmx,fma,bmi,bmi2") // New judges. Test with assert(__builtin_cpu_supports("avx2")); // #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native") // Atcoder // #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma") /* #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; - insert(x) - find_by_order(k): return iterator to the k-th smallest element - order_of_key(x): the number of elements that are strictly smaller */ #include<bits/stdc++.h> using namespace std; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); uniform_real_distribution<> pp(0.0,1.0); #define int long long #define ld long double #define pii pair<int,int> #define piii pair<pii,int> #define fi first #define se second const int inf=1e18; int mod; const int maxn=250005; const int bl=650; const int maxs=405; const int maxm=250005; const int maxq=500005; const int maxl=20; const int maxa=250000; const int root=3; /* int power(int a,int n){ int res=1; while(n){ if(n&1) res=res*a%mod; a=a*a%mod;n>>=1; } return res; } const int iroot=power(3,mod-2); */ const int base=101; void solve(){ int n;cin >> n >> mod; vector<vector<int>> edge(n+1),mul(n+1,vector<int>(41,1)); vector<int> h(n+1),par(n+1); for(int i=1;i<n;i++){ int u,v;cin >> u >> v; edge[u].push_back(v); edge[v].push_back(u); } for(int i=1;i<=n;i++) cin >> h[i]; function<void(int,int)> dfs = [&](int u,int p){ par[u]=p; for(int v:edge[u]){ if(v==p) continue; dfs(v,u); } }; dfs(1,0); int q;cin >> q; while(q--){ int id,x,d,k;cin >> id >> x; if(id==1){ cin >> d >> k; while(d && x>1){ mul[x][d]=mul[x][d]*k%mod; mul[x][d-1]=mul[x][d-1]*k%mod; x=par[x];d--; } for(int i=d;i>=0;i--) mul[x][i]=mul[x][i]*k%mod; } else{ int res=h[x]; for(int i=0;i<=40;i++){ res=res*mul[x][i]%mod; x=par[x]; } cout << res << '\n'; } } } signed main(){ ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL); int test=1;//cin >> test; while(test--) solve(); }
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