Submission #760255

#	Time	Username	Problem	Language	Result	Execution time	Memory
760255		OrazB	Money (IZhO17_money)	C++14	25 / 100	1590 ms	2764 KiB

money

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
             tree_order_statistics_node_update>
    ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <int, int>
#define pb push_back
#define ff first
#define ss second

int n, mn, a[N], c[N];
vector<int> E[N];

void bit(int x){
	if (x == n){
		for (int i = 0; i <= n; i++) E[i].clear();
		int idx = 0;
		for (int i = 1; i <= n; i++){
			E[idx].pb(a[i]);
			if (c[i]) idx++;
		}
		vector<int> vec;
		for (int i = 0; i <= idx; i++){
			int ind = vec.size()-1;
			while(ind >= 0 and vec[ind] > E[i][0]) ind--;
			ind++;
			for (int j = 0; j < (int)E[i].size(); j++){
				vec.insert(vec.begin()+ind+j, E[i][j]);
			}
		}
		for (int i = 1; i < n; i++){
			if (vec[i] < vec[i-1]) return;
		}
		mn = min(mn, idx+1);
		return;
	}
	for (int i = 0; i < 2; i++){
		c[x] = i;
		bit(x+1);
	}
}

int chk(){
	mn = 1e9;
	bit(1);
	return mn;
}

int main ()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cin >> n;
	for (int i = 1; i <= n; i++){
		cin >> a[i];
	}
	cout << chk();
}	

• Subtask 1: 9 / 9
• Subtask 2: 16 / 16
• Subtask 3: 0 / 20
• Subtask 4: 0 / 55