This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <int, int>
#define pb push_back
#define ff first
#define ss second
int n, mn, a[N], c[N];
vector<int> E[N];
void bit(int x){
if (x == n){
set<int> s;
vector<int> pos(n+1, 0);
for (int i = 1; i <= n; i++){s.insert(a[i]);E[i].clear();}
int idx = 0;
for (auto i : s) pos[i] = idx++;
idx = 0;
for (int i = 1; i <= n; i++){
E[idx].pb(a[i]);
if (c[i]) idx++;
}
vector<int> vec(n+1, 0);
for (int i = 0; i <= idx; i++){
int ind = pos[E[i][0]];
if (vec[ind]) ind++;
for (int j = 0; j < (int)E[i].size(); j++){
vec.insert(vec.begin()+ind+j, E[i][j]);
}
}
for (int i = 2; i <= n; i++){
if (vec[i] < vec[i-1]) return;
}
mn = min(mn, idx);
return;
}
for (int i = 0; i < 2; i++){
c[x] = i;
bit(x+1);
}
}
int chk(){
mn = 1e9;
bit(1);
return mn;
}
int main ()
{
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n;
for (int i = 1; i <= n; i++){
cin >> a[i];
}
cout << chk();
}
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