Submission #759968

#TimeUsernameProblemLanguageResultExecution timeMemory
759968OrazBCyberland (APIO23_cyberland)C++17
100 / 100
1479 ms73412 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <functional> using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; //set.find_by_order(x) x-position value //set.order_of_key(x) number of strictly less elements don't need *set.?? #define N 100005 #define wr cout << "Continue debugging\n"; #define all(x) (x).begin(), (x).end() #define ll long long int #define pii pair <double, int> #define pb push_back #define ff first #define ss second int vis[N]; set<pii> q[N]; vector<pair<int,int>> E[N]; vector<int> z; void dfs(int nd, int h){ vis[nd] = 1; for (auto i : E[nd]){ if (i.ff == h or vis[i.ff]) continue; dfs(i.ff, h); } } double solve(int n, int m, int k, int h, vector<int> x, vector<int> y, vector<int> c, vector<int> arr){ for (int i = 0; i < max(70,n); i++){ vis[i] = 0; E[i].clear(); if (i <= 70) q[i].clear(); } for (int i = 0; i < m; i++){ E[x[i]].pb({y[i], c[i]}); E[y[i]].pb({x[i], c[i]}); } z.clear(); z.pb(0); vector<vector<double>> dis(min(73,k+2), vector<double>(n+1, 1e15)); dfs(0, h); for (int i = 0; i < n; i++) if (!arr[i] and vis[i]) z.pb(i); double ans = 1e15; for (auto i : z){ dis[0][i] = 0; q[0].insert({0, i}); } for (int i = 0; i <= min(k,70); i++){ while(!q[i].empty()){ int x = (*q[i].begin()).ss; q[i].erase(q[i].begin()); if (x == h) continue; for (auto j : E[x]){ double res = dis[i][x]+j.ss; if (dis[i][j.ff] > res){ dis[i][j.ff] = res; q[i].insert({dis[i][j.ff], j.ff}); } if (arr[j.ff] == 2){ res /= 2; if (dis[i+1][j.ff] > res){ dis[i+1][j.ff] = res; q[i+1].insert({dis[i+1][j.ff], j.ff}); } } } } ans = min(ans, dis[i][h]); } if (ans == 1e15) return double(-1); return ans; } // int main () // { // int n, m, k, h; // cin >> n >> m >> k >> h; // vector<int> x(m), y(m), c(m), arr(n); // for (int i = 0; i < m; i++){ // cin >> x[i] >> y[i] >> c[i]; // } // for (int i = 0; i < n; i++) cin >> arr[i]; // cout << solve(n,m,k,h,x,y,c,arr); // }
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