Submission #759667

#TimeUsernameProblemLanguageResultExecution timeMemory
759667dooweyTreasure (different grader from official contest) (CEOI13_treasure2)C++14
0 / 100
2 ms468 KiB
#include <bits/stdc++.h> #include "treasure.h" using namespace std; typedef pair<int, int> pii; #define fi first #define se second #define mp make_pair map<pair<pii,pii>, int> Q; int ask(int i0, int j0, int i1, int j1){ if(i0 > i1 || j0 > j1) return 0; return countTreasure(i0,j0,i1,j1); pair<pii, pii> rect = mp(mp(i0,j0), mp(i1,j1)); if(Q.count(rect)){ return Q[rect]; } return Q[rect]=countTreasure(i0,j0,i1,j1); } int n; int get_cost(int i0, int j0, int i1, int j1){ if(i0 > i1 || j0 > j1) return 0; //if(Q.count(mp(mp(i0,j0), mp(i1,j1)))) return 0; return n * n - (i1 - i0 + 1) * (j1 - j0 + 1) + 1; } void findTreasure (int _n) { n = _n; int cost0; int cost1; int cost2; int cost3; int cur_value; vector<pii> ans; for(int i = 1; i <= n; i ++ ){ for(int j = 1; j <= n; j ++ ){ cost0 = get_cost(1, 1, i, j) + get_cost(1, 1, i - 1, j) + get_cost(1, 1, i, j - 1) + get_cost(1, 1, i - 1, j - 1); cost1 = get_cost(1, j, i, n) + get_cost(1, j, i - 1, n) + get_cost(1, j + 1, i, n) + get_cost(1, j + 1, i - 1, n); cost2 = get_cost(i, 1, n, j) + get_cost(i, 1, n, j - 1) + get_cost(i + 1, 1, n, j) + get_cost(i + 1, 1, n, j - 1); cost3 = get_cost(i, j, n, n) + get_cost(i + 1, j, n, n) + get_cost(i, j + 1, n, n) + get_cost(i + 1, j + 1, n, n); cur_value = 0; if(cost0 <= cost1 && cost0 <= cost2 && cost0 <= cost3){ cur_value = ask(1, 1, i, j) - ask(1, 1, i - 1, j) - ask(1, 1, i, j - 1) + ask(1, 1, i - 1, j - 1); } else if(cost1 <= cost2 && cost1 <= cost3){ cur_value = ask(1, j, i, n) - ask(1, j, i - 1, n) - ask(1, j + 1, i, n) + ask(1, j + 1, i - 1, n); } else if(cost2 <= cost3){ cur_value = ask(i, 1, n, j) - ask(i, 1, n, j - 1) - ask(i + 1, 1, n, j) + ask(i + 1, 1, n, j - 1); } else{ cur_value = ask(i, j, n, n) - ask(i + 1, j, n, n) - ask(i, j + 1, n, n) + ask(i + 1, j + 1, n, n); } if(cur_value == 1) ans.push_back(mp(i, j)); } } for(auto x : ans) Report(x.fi, x.se); }
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