Submission #758997

#	Time	Username	Problem	Language	Result	Execution time	Memory
758997		bachhoangxuan	Foehn Phenomena (JOI17_foehn_phenomena)	C++17	100 / 100	86 ms	11464 KiB

foehn_phenomena

// Judges with GCC >= 12 only needs Ofast
// #pragma GCC optimize("O3,no-stack-protector,fast-math,unroll-loops,tree-vectorize")
// MLE optimization
// #pragma GCC optimize("conserve-stack")
// Old judges
// #pragma GCC target("sse4.2,popcnt,lzcnt,abm,mmx,fma,bmi,bmi2")
// New judges. Test with assert(__builtin_cpu_supports("avx2"));
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native")
// Atcoder
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma")
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
- insert(x)
- find_by_order(k): return iterator to the k-th smallest element
- order_of_key(x): the number of elements that are strictly smaller
*/
#include<bits/stdc++.h>
using namespace std;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
uniform_real_distribution<> pp(0.0,1.0);
#define int long long
#define ld long double
#define pii pair<int,int>
#define piii pair<int,pii>
#define fi first
#define se second
const int inf=1e18;
const int mod=998244353;
const int maxn=200005;
const int bl=650;
const int maxs=650;
const int maxm=200005;
const int maxq=500005;
const int maxl=20;
const int maxa=1000000;
const int root=3;
int power(int a,int n){
    int res=1;
    while(n){
        if(n&1) res=res*a%mod;
        a=a*a%mod;n>>=1;
    }
    return res;
}
const int iroot=power(3,mod-2);
const int base=101;

void solve(){
    int n,q,s,t,p,ans=0;cin >> n >> q >> s >> t >> p;
    vector<int> a(n,0);
    for(int i=0;i<n;i++){
        cin >> a[i];
        swap(a[i],p);a[i]-=p;
        ans+=(a[i]<0?s:t)*a[i];
    }
    while(q--){
        int l,r,x;cin >> l >> r >> x;l--;
        ans-=(a[l]<0?s:t)*a[l];
        a[l]-=x;
        ans+=(a[l]<0?s:t)*a[l];
        if(r<n){
            ans-=(a[r]<0?s:t)*a[r];
            a[r]+=x;
            ans+=(a[r]<0?s:t)*a[r];
        }
        cout << ans << '\n';
    }
}
signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);cout.tie(NULL);
    int test=1;//cin >> test;
    while(test--) solve();
}

• Subtask 1: 30 / 30
• Subtask 2: 10 / 10
• Subtask 3: 60 / 60