Submission #758977

#TimeUsernameProblemLanguageResultExecution timeMemory
758977bachhoangxuanBitaro the Brave (JOI19_ho_t1)C++17
100 / 100
348 ms212032 KiB
// Judges with GCC >= 12 only needs Ofast
// #pragma GCC optimize("O3,no-stack-protector,fast-math,unroll-loops,tree-vectorize")
// MLE optimization
// #pragma GCC optimize("conserve-stack")
// Old judges
// #pragma GCC target("sse4.2,popcnt,lzcnt,abm,mmx,fma,bmi,bmi2")
// New judges. Test with assert(__builtin_cpu_supports("avx2"));
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native")
// Atcoder
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma")
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
- insert(x)
- find_by_order(k): return iterator to the k-th smallest element
- order_of_key(x): the number of elements that are strictly smaller
*/
#include<bits/stdc++.h>
using namespace std;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
uniform_real_distribution<> pp(0.0,1.0);
#define int long long
#define ld long double
#define pii pair<int,int>
#define piii pair<int,pii>
#define fi first
#define se second
const int inf=1e18;
const int mod=998244353;
const int maxn=200005;
const int bl=650;
const int maxs=650;
const int maxm=200005;
const int maxq=500005;
const int maxl=20;
const int maxa=1000000;
const int root=3;
int power(int a,int n){
    int res=1;
    while(n){
        if(n&1) res=res*a%mod;
        a=a*a%mod;n>>=1;
    }
    return res;
}
const int iroot=power(3,mod-2);
const int base=101;

void solve(){
    int n,m;cin >> n >> m;
    vector<vector<int>> O(n,vector<int>(m,0)),I(n,vector<int>(m,0)),J(n,vector<int>(m,0));
    for(int i=0;i<n;i++){
        for(int j=0;j<m;j++){
            char c;cin >> c;
            if(c=='O') O[i][j]=1;
            else if(c=='I') I[i][j]=1;
            else J[i][j]=1;
        }
    }
    for(int i=0;i<n;i++){
        for(int j=m-2;j>=0;j--) O[i][j]+=O[i][j+1];
    }
    for(int i=0;i<m;i++){
        for(int j=n-2;j>=0;j--) I[j][i]+=I[j+1][i];
    }
    int ans=0;
    for(int i=0;i<n;i++){
        for(int j=0;j<m;j++) ans+=J[i][j]*O[i][j]*I[i][j];
    }
    cout << ans << '\n';
}
signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);cout.tie(NULL);
    int test=1;//cin >> test;
    while(test--) solve();
}
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