Submission #757951

#	Time	Username	Problem	Language	Result	Execution time	Memory
757951		BentoOreo	Towers (NOI22_towers)	C++14	5 / 100	1 ms	212 KiB

Main

#include <iostream>
#include <string>
#include <vector>
#include <map>
#include <stack>
#include <queue>
#include <unordered_map>
#include <deque>
#include <set>
#include <unordered_set>
#include <algorithm>
#define ll long long
using namespace std;
int max_count = 0;
unordered_map<int,pair<ll,ll> > copygarbage;
void recurse(unordered_map<int,pair<ll,ll> > gyms, ll level, int count){
    if(gyms.size() == 0){
        max_count = max(max_count,count);
    } else {
        for(auto elem: gyms){
            if(level <= elem.second.first){//if level less than level cap
                copygarbage = gyms;
                copygarbage.erase(elem.first);
                recurse(copygarbage, level + elem.second.second, count + 1);
            }
        }
        max_count = max(max_count,count);//if I exhaust all I still need to check lol
    }
}
int main(){
    //subtask 1 of problem 2 complete search dfs
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int n;
    cin >> n;
    if(n <= 3){
        unordered_map <int, vector<int> > towers;
        int x, y;
        for(int i = 0; i < n; i++){
            cin >> x >> y;
            towers[i] = {x,y,0,i};// last digit is to see if it has tower on top but we dk rn
        }
        if(n == 1){
            cout << 1 << endl;
        } else if (n == 2){
            cout << 11 << endl;
        } else {
            vector<int> t1 = towers[0];
            vector<int> t2 = towers[1];
            vector<int> t3 = towers[2];
            if((t1.at(0) == t2.at(0) && t2.at(0) == t3.at(0)) || (t1.at(1) == t2.at(1) && t2.at(1) == t3.at(1))){
                //if they are all in 1 line
                vector< vector<int> > stws = {t1,t2,t3};
                sort(stws.begin(),stws.end());
                //this should sort by either x or y.
                //now that they are in order
                stws.at(0).at(2) = 1;
                stws.at(1).at(2) = 0;
                stws.at(2).at(2) = 1;
                towers[stws.at(0).at(3)] = stws.at(0);
                towers[stws.at(1).at(3)] = stws.at(1);
                towers[stws.at(2).at(3)] = stws.at(2);
                for(int i = 0; i < 3; i++){
                    cout << towers[i].at(2);
                }
                cout << endl;
            } else {
                cout << 111 << endl;

            }
        }
    } else { 
        cout << "AHHHH" << endl;
    }
}

• Subtask 1: 5 / 5
• Subtask 2: 0 / 11
• Subtask 3: 0 / 7
• Subtask 4: 0 / 6
• Subtask 5: 0 / 31
• Subtask 6: 0 / 21
• Subtask 7: 0 / 19