Submission #757261

#	Time	Username	Problem	Language	Result	Execution time	Memory
757261		hulahula3247	Bitaro, who Leaps through Time (JOI19_timeleap)	C++17	0 / 100	533 ms	102828 KiB

timeleap

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
#define all(v) v.begin(), v.end()
const ll INF = 0x3f3f3f3f;
ll N, Q;

struct Node {
    ll L, R, P, T;
    Node operator+(const Node &rhs) const {
        Node ret;
        ret.L = min(max(L, rhs.L), rhs.R);
        ret.R = max(min(R, rhs.R), rhs.L);
        ret.P = max(P, rhs.P);
        ret.T = T + rhs.T + max(ll(0), (min(P, ret.L)-L));
        return ret;
    }
};

struct Seg {

    Node tree[1200050];
    Node arr[300050];
    
    void b1(ll n, ll s, ll e) {
        if (s == e) {
            tree[n] = arr[s];
            return;
        }
        ll m = (s+e)/2;
        b1(2*n, s, m); b1(2*n+1, m+1, e);
        tree[n] = tree[2*n] + tree[2*n+1];
    }

    void u1(ll n, ll s, ll e, ll idx, ll l, ll r) {
        if (s == e) {
            tree[n] = {l, r, l, 0};
            return;
        }
        ll m = (s+e)/2;
        if (idx <= m) u1(2*n, s, m, idx, l, r);
        else u1(2*n+1, m+1, e, idx, l, r);
        tree[n] = tree[2*n] + tree[2*n+1];
    }

    Node q1(ll n, ll s, ll e, ll l, ll r) {
        if (l <= s && e <= r) return tree[n];
        if (s > r || e < l) return {-1, INF, -1, 0};
        ll m = (s+e)/2;
        return q1(2*n, s, m, l, r) + q1(2*n+1, m+1, e, l, r);
    }

    ll q2(ll x1, ll x2, ll t1, ll t2) {
        Node start = {t1, t1, t1, 0};
        Node end = {t2, t2, t2, 0};
        Node mid = q1(1, 0, N-1, x1, x2);
        Node ret = (start + mid) + end;
        return ret.T + max(ll(0), ret.P-ret.L);
    }

}seg1, seg2;

void solve() {

	cin >> N >> Q;
    N--;
	for (int i = 0; i < N; i++) {
		ll l, r;
		cin >> l >> r;
		seg1.arr[i] = {N-1-i+l, N-2-i+r, N-1-i+l, 0};
		seg2.arr[N-1-i] = {l+i, r+i-1, l+i, 0};
	}
    seg1.b1(1, 0, N-1); seg2.b1(1, 0, N-1);

    for (int i = 0; i < Q; i++) {
		int t; cin >> t;
		if (t == 1) {
			ll a, b, c;
			cin >> a >> b >> c;
            a -= 1;
            seg1.u1(1, 0, N-1, a, N-1-a+b, N-2-a+c);
            seg2.u1(1, 0, N-1, N-1-a, a+b, a-1+c);
		}
		else {
			ll x1, t1, x2, t2;
			cin >> x1 >> t1 >> x2 >> t2;
			bool fg = 0;
			if (x1 > x2) {
				fg = 1;
				swap(x1, x2);
                x1 -= 1;
                x2 -= 2;
                x1 = N-1-x1;
                x2 = N-1-x2;
                swap(x1, x2);
			}
            else {
                x1 -= 1;
                x2 -= 2;
            }
			t1 += N-1-x1;
			t2 += N-2-x2;
			if (!fg) cout << seg1.q2(x1, x2, t1, t2) << '\n';
			else cout << seg2.q2(x1, x2, t1, t2) << '\n';
		}
	}

}

int main(void) {

	ios::sync_with_stdio(false);
	cin.tie(0);
	int T = 1;
	//cin >> T;
	while (T--) solve();
	return 0;
}

• Subtask 1: 0 / 4
• Subtask 2: 0 / 30
• Subtask 3: 0 / 66