Submission #756249

#	Time	Username	Problem	Language	Result	Execution time	Memory
756249		sugartheanh	Svjetlo (COCI20_svjetlo)	C++14	60 / 110	380 ms	97924 KiB

svjetlo

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

const int N = 5e5 + 7;
const int INF = 1e9 + 7;

int n, dp[N][2][3], nxtDp[2][3], cnt[N];
string s;
vector<int> adj[N];

void Dfs(int u, int p){
    int state = s[u] - '0';
    cnt[u] = (state == 0);
    for(int v : adj[u]){
        if (v == p)
            continue;
        Dfs(v, u);
        cnt[u] += cnt[v];
    }
    if (cnt[u] == 0)
        return;

    dp[u][state ^ 1][0] = 1;
    dp[u][state ^ 1][1] = 1;
    dp[u][state ^ 1][2] = 1;
    for(int v : adj[u]){
        if (v == p || cnt[v] == 0)
            continue;
        memset(nxtDp, 0x3f, sizeof(nxtDp));

        for(int s = 0; s < 2; s++){
            nxtDp[s][0] = min(nxtDp[s][0], dp[u][s ^ 1][0] + dp[v][1][0] + 1);
            nxtDp[s][0] = min(nxtDp[s][0], dp[u][s][0] + dp[v][0][0] + 3);

            nxtDp[s][1] = min(nxtDp[s][1], dp[u][s ^ 1][1] + dp[v][1][0] + 1);
            nxtDp[s][1] = min(nxtDp[s][1], dp[u][s][1] + dp[v][0][0] + 3);
            nxtDp[s][1] = min(nxtDp[s][1], dp[u][s][0] + dp[v][1][1]);
            nxtDp[s][1] = min(nxtDp[s][1], dp[u][s ^ 1][0] + dp[v][0][1] + 2);

            nxtDp[s][2] = min(nxtDp[s][2], dp[u][s][1] + dp[v][1][1]);
            nxtDp[s][2] = min(nxtDp[s][2], dp[u][s ^ 1][1] + dp[v][0][1] + 2);
            nxtDp[s][2] = min(nxtDp[s][2], dp[u][s][0] + dp[v][0][2] + 1);
            nxtDp[s][2] = min(nxtDp[s][2], dp[u][s ^ 1][0] + dp[v][1][2] + 3);
            nxtDp[s][2] = min(nxtDp[s][2], dp[u][s ^ 1][2] + dp[v][1][0] + 1);
            nxtDp[s][2] = min(nxtDp[s][2], dp[u][s][2] + dp[v][0][0] + 3);

        }
        for(int s = 0; s < 2; s++)
            for(int i = 0; i < 3; i++)
                dp[u][s][i] = nxtDp[s][i];
    }
}

int main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    cin >> n >> s;
    s = '*' + s;
    for(int i = 1; i < n; i++){
        int u, v;
        cin >> u >> v;
        adj[u].push_back(v);
        adj[v].push_back(u);
    }

    memset(dp, 0x3f, sizeof(dp));
    int root = 1;
    Dfs(root, -1);
    cout << dp[root][1][2];

    return 0;
}

• Subtask 1: 0 / 20
• Subtask 2: 30 / 30
• Subtask 3: 30 / 30
• Subtask 4: 0 / 30