Submission #753915

#	Time	Username	Problem	Language	Result	Execution time	Memory
753915		valerikk	Wiring (IOI17_wiring)	C++17	100 / 100	54 ms	10184 KiB

wiring

#include "wiring.h"
#include <bits/stdc++.h>

using namespace std;

const long long INF = 2e18;

long long getcost(vector<int> r, vector<int> b) {
	int n = r.size();
	int m = b.size();
	long long ret = 0;
	if (n < m) {
		for (int i = 0; i < n; ++i) {
			ret -= r[i];
		}
		ret -= (m - n) * 1ll * r[n - 1];
		for (int i = 0; i < m; ++i) {
			ret += b[i];
		}
	} else {
		for (int i = 0; i < n; ++i) {
			ret -= r[i];
		}
		ret += (n - m) * 1ll * b[0];
		for (int i = 0; i < m; ++i) {
			ret += b[i];
		}
	}
	return ret;
}

long long min_total_length(std::vector<int> r, std::vector<int> b) {
	int n = r.size();
	int m = b.size();
	vector<pair<int, int>> kek;
	for (int i = 0; i < n; ++i) {
		kek.push_back({r[i], 0});
	}
	for (int i = 0; i < m; ++i) {
		kek.push_back({b[i], 1});
	}
	sort(kek.begin(), kek.end());
	vector<long long> dp(n + m + 1, INF);
	vector<long long> dp1(n + m + 1, INF), dp2(n + m + 1, INF);
	dp[0] = 0;
	for (int i = 0; i < n + m; ++i) {
		dp[i] = min(dp[i], dp[i + 1]);
		if (i < n + m - 1 && kek[i].second != kek[i + 1].second) {
			int prv = i;
			while (prv > 0 && kek[prv - 1].second == kek[i].second) {
				--prv;
			}
			int nxt = i + 1;
			while (nxt < n + m - 1 && kek[nxt + 1].second == kek[i + 1].second) {
				++nxt;
			}
			for (int j = i + 2; j <= nxt + 1; ++j) {
				dp1[j] = INF;
				dp2[j] = INF;
			}
			long long sum = 0;
			for (int j = 0; i + j + 1 <= nxt && i - j >= prv; ++j) {
				sum -= kek[i - j].first;
				sum += kek[i + j + 1].first;
				dp1[i + j + 2] = min(dp1[i + j + 2], dp[i - j] + sum);
				dp2[i + j + 2] = min(dp2[i + j + 2], dp[i - j] + sum);
			}
			if (nxt - i < i - prv + 1) {
				int d = nxt - i;
				for (int j = i - d; j >= prv; --j) {
					sum -= kek[j].first;
					sum += kek[i + 1].first;
					dp2[nxt + 1] = min(dp2[nxt + 1], dp[j] + sum);
				}
			}
			for (int j = i + 2; j + 1 <= nxt + 1; ++j) {
				if (dp1[j] != INF) {
					dp1[j + 1] = min(dp1[j + 1], dp1[j] + kek[j].first - kek[i].first);
				}
			}
			for (int j = nxt + 1; j >= i + 3; --j) {
				if (dp2[j] != INF) {
					dp2[j - 1] = min(dp2[j - 1], dp2[j] - kek[j - 1].first + kek[i + 1].first);
				}
			}
			for (int j = i + 2; j <= nxt + 1; ++j) {
				dp[j] = min(dp[j], dp1[j]);
				dp[j] = min(dp[j], dp2[j]);
				if (j > 0) {
					dp[j - 1] = min(dp[j - 1], dp[j]);
					dp[j - 1] = min(dp[j - 1], dp[j]);
				}
			}
		}
		// for (int j = 0; j <= n + m; ++j) {
		// 	cout << dp[j] << " " << kek[j].second << " ";
		// }
		// cout << endl;

		// bool was = 0;
		// vector<int> r1, b1;
		// for (int j = i; j < n + m; ++j) {
		// 	if (was) {
		// 		if (kek[j].second == kek[i].second) {
		// 			break;
		// 		}
		// 	}
		// 	if (kek[j].second == kek[i].second) {
		// 		r1.push_back(kek[j].first);
		// 	} else {
		// 		was = 1;
		// 		b1.push_back(kek[j].first);
		// 	}
		// 	if (was) {
		// 		long long cost = getcost(r1, b1);
		// 		dp[j + 1] = min(dp[j + 1], dp[i] + cost);
		// 	}
		// }
	}
	return dp[n + m];
}

• Subtask 1: 7 / 7
• Subtask 2: 13 / 13
• Subtask 3: 10 / 10
• Subtask 4: 25 / 25
• Subtask 5: 45 / 45