# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
75176 | bogdan10bos | Commuter Pass (JOI18_commuter_pass) | C++14 | 520 ms | 15856 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
//#define FILE_IO
typedef long long LL;
typedef pair<int, int> pii;
typedef pair<LL, int> pli;
int N, M, S, T, U, V;
LL d[100005][3];
vector<int> pth;
vector<pii> edg[100005];
priority_queue< pli, vector<pli>, greater<pli> > pq;
class Dijkstra
{
public:
int nod;
vector<LL> d;
void dijkstra(int _nod)
{
d.resize(N + 5);
nod = _nod;
for(int i = 1; i <= N; i++) d[i] = 1LL << 60;
while(!pq.empty()) pq.pop();
d[nod] = 0;
pq.push({0LL, nod});
while(!pq.empty())
{
int nod = pq.top().second;
LL val = pq.top().first;
pq.pop();
if(d[nod] != val) continue;
for(auto &e: edg[nod])
if(d[e.first] > val + e.second)
{
d[e.first] = val + e.second;
pq.push({val + e.second, e.first});
}
}
}
LL getd(int x) { return d[x]; }
}dS, dT, dU, dV, djk[305];
int main()
{
#ifdef FILE_IO
freopen("1.in", "r", stdin);
freopen("1.out", "w", stdout);
#endif
scanf("%d%d", &N, &M);
scanf("%d%d", &S, &T);
scanf("%d%d", &U, &V);
for(int i = 1; i <= M; i++)
{
int x, y, z;
scanf("%d%d%d", &x, &y, &z);
edg[x].push_back({y, z});
edg[y].push_back({x, z});
}
dS.dijkstra(S);
dT.dijkstra(T);
dU.dijkstra(U);
dV.dijkstra(V);
LL ans = dU.getd(V);
LL dST = dS.getd(T);
for(int i = 1; i <= N; i++)
d[i][0] = d[i][1] = d[i][2] = 1LL << 60;
d[S][0] = 0;
d[S][1] = dU.getd(S);
d[S][2] = dV.getd(S);
pq.push({0LL, S});
while(!pq.empty())
{
int nod = pq.top().second;
LL val = pq.top().first;
pq.pop();
if(d[nod][0] != val) continue;
d[nod][1] = min(d[S][1], dU.getd(nod));
d[nod][2] = min(d[S][2], dV.getd(nod));
if(val + dT.getd(nod) == dST)
{
ans = min(ans, d[nod][1] + dV.getd(nod));
ans = min(ans, d[nod][2] + dU.getd(nod));
}
for(auto e: edg[nod])
{
if(d[e.first][0] > val + e.second)
{
d[e.first][0] = val + e.second;
d[e.first][1] = d[nod][1];
d[e.first][2] = d[nod][2];
pq.push({val + e.second, e.first});
}
else if(d[e.first][0] == val + e.second)
{
d[e.first][1] = min(d[e.first][1], d[nod][1]);
d[e.first][2] = min(d[e.first][2], d[nod][2]);
}
}
}
printf("%lld\n", ans);
return 0;
}
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