This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("Ofast,O1,O2,O3,unroll-loops")
#pragma GCC target("avx,avx2")
#include "cyberland.h"
#include <bits/stdc++.h>
using namespace std;
vector<vector<pair<int, double>>> g;
vector<bool> used;
vector<int> zeros;
void dfs(int v, const vector<int> &arr){
used[v] = true;
if (arr[v] == 0 || v == 0) zeros.push_back(v);
for (auto [u, w] : g[v]){
if (!used[u]){
dfs(u, arr);
}
}
}
double solve(int N, int M, int K, int H, std::vector<int> x, std::vector<int> y, std::vector<int> c, std::vector<int> arr) {
K = min(K, 70);
g.clear();
g.resize(N);
for (int i = 0; i < M; i++) {
if (y[i] != H) g[x[i]].emplace_back(y[i], c[i]);
if (x[i] != H) g[y[i]].emplace_back(x[i], c[i]);
}
zeros.clear();
used.assign(N, false);
dfs(0, arr);
const double INF = 2e15;
const int T = 5;
vector<vector<double>> dp(N, vector<double>(T, INF));
for (int v : zeros){
dp[v].assign(T, 0);
}
double ans = INF;
for (int k = 0; k <= K; k++) {
if (k > 0) {
for (int i = 0; i < N; i++) {
if (dp[i][(k + T - 1) % T] == INF) continue;
dp[i][k % T] = min(dp[i][k % T], dp[i][(k + T - 1) % T]);
if (arr[i] == 0) {
dp[i][k % T] = 0;
}
}
}
priority_queue<pair<double, int>> pq;
for (int i = 0; i < N; i++) {
if (dp[i][k % T] != INF) pq.emplace(-dp[i][k % T], i);
}
vector<bool> processed(N, false);
while (!pq.empty()) {
int v = pq.top().second;
pq.pop();
if (processed[v]) continue;
processed[v] = true;
for (auto [u, w]: g[v]) {
dp[u][k % T] = min(dp[u][k % T], dp[v][k % T] + w);
if (arr[u] == 0) {
dp[u][k % T] = 0;
}
if (arr[u] == 2 && k < K) {
dp[u][(k + 1) % T] = min(dp[u][(k + 1) % T], (dp[v][k % T] + w) / 2);
}
pq.emplace(-dp[u][k % T], u);
}
}
for (int v = 0; v < N; v++){
dp[v][(k + T - 2) % T] = INF;
}
for (int v : zeros) dp[v][(k + T - 2) % T] = 0;
for (auto [v, w]: g[H]) {
if (dp[v][k % T] == INF) continue;
if (arr[H] == 0) return 0;
ans = min(ans, dp[v][k % T] + w);
if (k < K && arr[H] == 2) {
ans = min(ans, (dp[v][k % T] + w) / 2);
}
}
}
if (ans == INF) return -1;
return ans;
}
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