Submission #748723

#	Time	Username	Problem	Language	Result	Execution time	Memory
748723		PixelCat	Selling RNA Strands (JOI16_selling_rna)	C++14	35 / 100	530 ms	895688 KiB

selling_rna

/*     code by PixelCat     */
/*         meow owo         */

#include <bits/stdc++.h>
// #define int LL  //__int128
#define double long double
using namespace std;
using LL = long long;
// using i128 = __int128_t;
using ull = unsigned long long;
using pii = pair<int, int>;

#define For(i, a, b) for (int i = a; i <= b; i++)
#define Fors(i, a, b, s) for (int i = a; i <= b; i += s)
#define Forr(i, a, b) for (int i = a; i >= b; i--)
#define F first
#define S second

#define eb emplace_back
#define all(x) x.begin(), x.end()
#define sz(x) ((int)x.size())
#define mkp make_pair

#define MOD (int)(998244353)
// #define MOD (int)((LL)1'000'000'007)
#define INF (int)(4e18)
#define EPS (1e-6)

namespace PixelCat {

#ifdef NYAOWO
#include "/home/pixelcat/yodayo/meow/library/debug.hpp"
inline void USACO(const string &s) {
    cerr << "USACO: " << s << "\n";
}

#else
#define debug(...)
inline void timer() {}
inline void USACO(const string &s) {
    freopen((s + ".in").c_str(), "r", stdin);
    freopen((s + ".out").c_str(), "w", stdout);
}

#endif

inline void NYA() {
    ios::sync_with_stdio(false);
    cin.tie(0);
}
inline int gcd(int a, int b) {
    return __gcd(a, b);
}
inline int lcm(int a, int b) {
    return a / gcd(a, b) * b;
}
int fpow(int b, int p, const int &mod = MOD) {
    int ans = 1;
    for (; p; p >>= 1, b = b * b % mod)
        if (p & 1) ans = ans * b % mod;
    return ans;
}
template <typename T>
inline void chmin(T &_a, const T &_b) {
    if (_b < _a) _a = _b;
}
template <typename T>
inline void chmax(T &_a, const T &_b) {
    if (_b > _a) _a = _b;
}
mt19937_64 rng(
    chrono::steady_clock::now().time_since_epoch().count());

} // namespace PixelCat
using namespace PixelCat;

const int MAXN = 100010;   // N, Q
const int MAXS = 2000010;  // total # of characters
const int MAXCH = 26;       // charcters count

using nodeid = int;
struct Trie {
    nodeid cur_node, rt;
    int dfs_time;
    nodeid nxt[MAXS][MAXCH];
    int l[MAXS];
    int r[MAXS];
    vector<nodeid> end_node;

    int ord(const char &ch) {
        switch(ch) {
            case 'A':
                return 0;
            case 'U':
                return 1;
            case 'C':
                return 2;
            default:
                return 3;
        }
    }
    nodeid new_node() {
        cur_node++;
        return cur_node;
    }
    void init() {
        memset(nxt, 0, sizeof(nxt));
        memset(l, 0, sizeof(l));
        memset(r, -1, sizeof(r));
        cur_node = 0;
        rt = new_node();
    }
    void insert(const string &s) {
        int nd = rt;
        for(const char &ch:s) {
            nodeid &nnd = nxt[nd][ord(ch)];
            if(!nnd) nnd = new_node();
            nd = nnd;
        }
        end_node.eb(nd);
        r[nd]++;
    }
    void _dfs(int nd) {
        l[nd] += dfs_time;
        r[nd] += dfs_time;
        dfs_time = r[nd] + 1;
        For(ch, 0, MAXCH - 1) {
            nodeid nnd = nxt[nd][ch];
            if(nnd) {
                _dfs(nnd);
                r[nd] = r[nnd];
            }
        }
    }
    void build(int* pos) {
        dfs_time = 1;
        _dfs(rt);
        For(i, 0, sz(end_node) - 1) {
            nodeid nd = end_node[i];
            pos[i + 1] = l[nd];
        }
    }
    pii find(const string &s) {
        int nd = rt;
        for(const char &ch:s) {
            nodeid &nnd = nxt[nd][ord(ch)];
            if(!nnd) return pii(-1, -1);
            nd = nnd;
        }
        return pii(l[nd], r[nd]);
    }
} tt, tr;

#define LO(x) ((x) & (-(x)))
struct BIT {
    int n;
    int a[MAXN];
    void init(int _n) {
        n = _n;
        memset(a, 0, sizeof(a));
    }
    void add(int i, int x) {
        while(i <= n) {
            a[i] += x;
            i += LO(i);
        }
    }
    int ask(int i) {
        int res = 0;
        while(i) {
            res += a[i];
            i -= LO(i);
        }
        return res;
    }
    int ask(int l, int r) {
        return ask(r) - ask(l - 1);
    }
} bit;

struct SweepingLine {
    struct Event {
        int x, yl, yr, id;
    }; vector<Event> ev;
    int ans[MAXN];
    void init() {
        memset(ans, 0, sizeof(ans));
    }
    void add_pt(int x, int y) {
        ev.eb((Event){x, y, 0, 0});
    }
    void add_qry(int id, pii x, pii y) {
        ev.eb((Event){x.F - 1, y.F, y.S, -id});
        ev.eb((Event){x.S, y.F, y.S, id});
    }
    int* solve(int n) {
        sort(all(ev), [&](const Event &ea, const Event &eb) {
            if(ea.x != eb.x) return ea.x < eb.x;
            return ea.id == 0;
        });
        reverse(all(ev));
        bit.init(n);
        while(!ev.empty()) {
            Event e = ev.back();
            ev.pop_back();
            if(e.id == 0) {
                bit.add(e.yl, 1);
            } else if(e.id > 0) {
                ans[e.id] += bit.ask(e.yl, e.yr);
            } else {
                ans[-e.id] -= bit.ask(e.yl, e.yr);
            }
        }
        return ans;
    }
} swp;

int posx[MAXN];
int posy[MAXN];

int32_t main() {
    NYA();
    // nyaacho >/////<
    cerr << (sizeof(tt) * 2 + sizeof(bit) + sizeof(swp) + sizeof(posx) * 2) << "\n";

    int n, q; cin >> n >> q;

    tt.init();
    tr.init();
    For(i, 1, n) {
        string s; cin >> s;
        tt.insert(s);
        reverse(all(s));
        tr.insert(s);
    }

    tt.build(posx);
    tr.build(posy);
    swp.init();
    For(i, 1, n) {
        swp.add_pt(posx[i], posy[i]);
    }
    
    For(i, 1, q) {
        string sx, sy;
        cin >> sx >> sy;
        pii px = tt.find(sx);
        reverse(all(sy));
        pii py = tr.find(sy);

        if(px.F >= 0 && py.F >= 0) {
            swp.add_qry(i, px, py);
        }
    }

    int* ans = swp.solve(n);
    For(i, 1, q) {
        cout << ans[i] << "\n";
    }
    return 0;
}

/*

2 3
AUGC
AGC
G C
AU C
A C

=> 0 1 2


3 3
AA
AA
AGA
AA AA
AG GA
AG GA

=> 2 1 1


8 7
GCGCUACCCCAACACAAGGCAAGAUAUA
G
GGAC
GCGG
U
GCGCUACCCCAACACAAGGCAAGAUGGUC
GCCG
GCGCUGA
GCGCUACCC A
GCGCUACCCC AC
GCG C
GCGC A
G G
G C
G GGA

=> 1 0 1 2 3 2 0

*/

• Subtask 1: 10 / 10
• Subtask 2: 25 / 25
• Subtask 3: 0 / 25
• Subtask 4: 0 / 40