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답안 #743949

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
743949 2023-05-18T06:38:19 Z jamielim Izvanzemaljci (COI21_izvanzemaljci) C++14
5 / 100
 190 ms 25400 KB 
#include <bits/stdc++.h>
using namespace std;

#define int long long

#define fi first
#define se second
#define mp make_pair
#define pb emplace_back
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)x.size()
typedef long long ll;
typedef pair<int,int> ii;
typedef pair<ii,ii> i4;
typedef vector<int> vi;
const int MOD=1000000007;
const int INF=1012345678;
const ll LLINF=1012345678012345678LL;
const double PI=3.1415926536;
const double EPS=1e-14;

int n,k;
vector<ii> all;
map<int,vector<int> > row,col;

vector<int> find_one_square(vector<ii> v){
	if(SZ(v)==0)return {0,0,1};
	int minx=LLINF,maxx=-LLINF,miny=LLINF,maxy=-LLINF;
	for(ii i:v){
		minx=min(minx,i.fi);
		maxx=max(maxx,i.fi);
		miny=min(miny,i.se);
		maxy=max(maxy,i.se);
	}
	int l=max(1LL,max(maxx-minx,maxy-miny));
	return {minx,miny,l};
}

bool disjoint(vector<int> v1,vector<int> v2){
	return (v1[0]+v1[2]<v2[0])||(v2[0]+v2[2]<v1[0])||(v1[1]+v1[2]<v2[1])||(v2[1]+v2[2]<v1[1]);
}

int32_t main(){
	scanf("%lld%lld",&n,&k);
	int x,y;
	for(int i=0;i<n;i++){
		scanf("%lld%lld",&x,&y);
		all.pb(x,y);
		row[y].pb(x);
		col[x].pb(y);
	}
	if(k==1){
		vector<int> ans=find_one_square(all);
		printf("%lld %lld %lld\n",ans[0],ans[1],ans[2]);
	}else if(k==2){
		int le=3*INF;
		vector<int> ans[2];
		
		vector<ii> pre,pst;
		vector<int> a1,a2;int x;
		for(auto it=row.begin();it!=row.end();++it){
			sort(ALL(it->se));
			for(int i:it->se)pst.pb(i,it->fi);
		}
		reverse(ALL(pst));
		for(auto it=row.begin();it!=row.end();++it){
			for(int i=0;i<SZ(it->se);i++){
				a1=find_one_square(pre);a2=find_one_square(pst);
				x=max(a1[2],a2[2]);
				if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
				pre.pb(pst.back());
				pst.pop_back();
			}
			a1=find_one_square(pre);a2=find_one_square(pst);
			x=max(a1[2],a2[2]);
			if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
			
			for(int i:it->se){pst.pb(i,it->fi);pre.pop_back();}
			for(int i=0;i<SZ(it->se);i++){
				a1=find_one_square(pre);a2=find_one_square(pst);
				x=max(a1[2],a2[2]);
				if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
				pre.pb(pst.back());
				pst.pop_back();
			}
			a1=find_one_square(pre);a2=find_one_square(pst);
			x=max(a1[2],a2[2]);
			if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
			
		}
		pre.clear();pst.clear();
		for(auto it=col.begin();it!=col.end();++it){
			sort(ALL(it->se));
			for(int i:it->se)pst.pb(it->fi,i);
		}
		reverse(ALL(pst));
		for(auto it=col.begin();it!=col.end();++it){
			for(int i=0;i<SZ(it->se);i++){
				a1=find_one_square(pre);a2=find_one_square(pst);
				x=max(a1[2],a2[2]);
				if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
				pre.pb(pst.back());
				pst.pop_back();
			}
			a1=find_one_square(pre);a2=find_one_square(pst);
			x=max(a1[2],a2[2]);
			if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
			
			for(int i:it->se){pst.pb(it->fi,i);pre.pop_back();}
			for(int i=0;i<SZ(it->se);i++){
				a1=find_one_square(pre);a2=find_one_square(pst);
				x=max(a1[2],a2[2]);
				if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
				pre.pb(pst.back());
				pst.pop_back();
			}
			a1=find_one_square(pre);a2=find_one_square(pst);
			x=max(a1[2],a2[2]);
			if(x<le&&disjoint(a1,a2)){le=x;ans[0]=a1;ans[1]=a2;}
			
		}
		for(int i=0;i<2;i++){for(int j=0;j<3;j++)printf("%lld ",ans[i][j]);printf("\n");}
	}else{
		
	}
}
/*
5 2
1 3
3 1
5 5
5 10
7 7
*/

Compilation message

izvanzemaljci.cpp: In function 'int32_t main()':
izvanzemaljci.cpp:44:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   44 |  scanf("%lld%lld",&n,&k);
      |  ~~~~~^~~~~~~~~~~~~~~~~~
izvanzemaljci.cpp:47:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   47 |   scanf("%lld%lld",&x,&y);
      |   ~~~~~^~~~~~~~~~~~~~~~~~

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 164 ms 25300 KB Output is correct
8 Correct 190 ms 25400 KB Output is correct
9 Correct 171 ms 25216 KB Output is correct
10 Correct 163 ms 25228 KB Output is correct
11 Correct 180 ms 25260 KB Output is correct

Subtask #2
0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Runtime error 1 ms 340 KB Execution killed with signal 11
4 Halted 0 ms 0 KB -

Subtask #3
0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 212 KB Unexpected end of file - int64 expected
2 Halted 0 ms 0 KB -

Subtask #4
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 468 KB Unexpected end of file - int64 expected
2 Halted 0 ms 0 KB -

Subtask #5
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 468 KB Unexpected end of file - int64 expected
2 Halted 0 ms 0 KB -