This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h>
using namespace std;
#define REP(i, s, e) for (int i = (s); i < (e); i++)
#define RREP(i, s, e) for (int i = (s); i >= (e); i--)
template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define SZ(_a) (int) _a.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;
#ifndef DEBUG
#define cerr if (0) cerr
#endif
const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 200005;
struct Point {
int x, y, i;
bool operator< (const Point &o) const {
if (x == o.x) return y < o.y;
return x < o.x;
}
Point& operator+= (const Point &o) {
x += o.x;
y += o.y;
return *this;
}
Point& operator-= (const Point &o) {
x -= o.x;
y -= o.y;
return *this;
}
ll cross(const Point& o) {
return (ll) x * o.y - (ll) y * o.x;
}
};
int n;
vi adj[MAXN];
Point pt[MAXN];
int ans[MAXN];
vi ch[MAXN];
int sub[MAXN];
void dfs(int u, int p) {
sub[u] = 1;
for (int v : adj[u]) {
if (v == p) {
continue;
}
ch[u].pb(v);
dfs(v, u);
sub[u] += sub[v];
}
}
void solve(int u, int l, int r) {
ans[pt[l].i] = u;
for (int v : ch[u]) {
solve(v, l + 1, l + sub[v]);
l += sub[v];
}
assert(l == r);
}
int main() {
#ifndef DEBUG
ios::sync_with_stdio(0), cin.tie(0);
#endif
cin >> n;
REP (i, 1, n) {
int u, v; cin >> u >> v;
adj[u].pb(v);
adj[v].pb(u);
}
REP (i, 0, n) {
cin >> pt[i].x >> pt[i].y;
pt[i].i = i;
}
sort(pt, pt + n);
RREP (i, n - 1, 0) {
pt[i] -= pt[0];
}
sort(pt + 1, pt + n, [&] (Point &l, Point &r) {
return l.cross(r) > 0;
});
int rt = -1;
REP (i, 1, n + 1) {
if (SZ(adj[i]) <= 2) {
rt = i;
break;
}
}
assert(rt != -1);
dfs(rt, -1);
solve(rt, 0, n - 1);
REP (i, 0, n) {
cout << ans[i] << ' ';
}
cout << '\n';
return 0;
}
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