Submission #741249

#TimeUsernameProblemLanguageResultExecution timeMemory
741249sunwukong123Kangaroo (CEOI16_kangaroo)C++14
0 / 100
1 ms340 KiB
#include <bits/stdc++.h> using namespace std; #define int long long #define FOR(i,s,e) for(int i = s; i <= (int)e; ++i) #define DEC(i,s,e) for(int i = s; i >= (int)e; --i) #define IAMSPEED ios_base::sync_with_stdio(false); cin.tie(0); #ifdef LOCAL #define db(x) cerr << #x << "=" << x << "\n" #define db2(x, y) cerr << #x << "=" << x << " , " << #y << "=" << y << "\n" #define db3(a,b,c) cerr<<#a<<"="<<a<<","<<#b<<"="<<b<<","<<#c<<"="<<c<<"\n" #define dbv(v) cerr << #v << ":"; for (auto ite : v) cerr << ite << ' '; cerr <<"\n" #define dbvp(v) cerr << #v << ":"; for (auto ite : v) cerr << "{" << ite.f << ',' << ite.s << "} "; cerr << "\n" #define dba(a,ss,ee) cerr << #a << ":"; FOR(ite,ss,ee) cerr << a[ite] << ' '; cerr << "\n" #define reach cerr << "LINE: " << __LINE__ << "\n"; #else #define reach #define db(x) #define db2(x,y) #define db3(a,b,c) #define dbv(v) #define dbvp(v) #define dba(a,ss,ee) #endif mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); #define pb push_back #define eb emplace_back #define all(x) (x).begin(), (x).end() #define f first #define s second #define g0(x) get<0>(x) #define g1(x) get<1>(x) #define g2(x) get<2>(x) #define g3(x) get<3>(x) typedef pair <int, int> pi; typedef tuple<int,int,int> ti3; typedef tuple<int,int,int,int> ti4; int rand(int a, int b) { return a + rng() % (b-a+1); } const int MOD = 1e9 + 7; const int inf = (int)1e9 + 500; const long long oo = (long long)1e18 + 500; template <typename T> void chmax(T& a, const T b) { a=max(a,b); } template <typename T> void chmin(T& a, const T b) { a=min(a,b); } const int MAXN = 2005; int n,a,b; int dp[MAXN][MAXN]; int32_t main() { IAMSPEED cin >> n >> a >> b; dp[0][0+1]=1; FOR(i,0,n-1){ FOR(j,-1,n){ if(dp[i][j+1]){ if(i+1==a){ dp[i+1][j+1]=(dp[i+1][j+1]+dp[i][j+1])%MOD; dp[i+1][j-1+1]=(dp[i+1][j-1+1]+dp[i][j+1])%MOD; } else if(i+1==b){ dp[i+1][j+1]=(dp[i+1][j+1]+dp[i][j+1])%MOD; dp[i+1][j-1+1]=(dp[i+1][j-1+1]+dp[i][j+1])%MOD; } else{ dp[i+1][j+1+1]=dp[i][j+1]*(j+1)%MOD; dp[i+1][j-1+1]=dp[i][j+1]*(j+(i>=a) && (i>=b))%MOD; } } } } cout<<dp[n][0]; }
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