Submission #741146

#TimeUsernameProblemLanguageResultExecution timeMemory
741146Dan4LifeJail (JOI22_jail)C++17
0 / 100
61 ms7892 KiB
#include <bits/stdc++.h> using namespace std; #define int long long #define fi first #define se second #define pb push_back #define all(a) a.begin(),a.end() const int mxN = (int)1.2e5; const int mxM = (int)500; const int LINF = (int)2e18; int n, m, Cycle; int ind[mxN], dis[mxM][mxN]; int s[mxM], t[mxM], vis[mxM]; vector<int> adj[mxN], adj2[mxN]; void dfs(int s, int p, int i){ if(p==-1) dis[i][s] = 0; else dis[i][s] = dis[i][p]+1; for(auto u : adj[s]) if(u!=p) dfs(u,s,i); } bool inPath(int x, int s, int t){ return (dis[ind[s]][x]+dis[ind[t]][x]==dis[ind[s]][t]); } void dfs2(int s){ vis[s] = 1; for(auto u : adj2[s]){ if(!vis[u]) dfs2(u); else if(vis[u]==1) { Cycle=1; return; } } vis[s]=2; } void solve(){ cin >> n; Cycle = 0; for(int i = 1; i <= n; i++) adj[i].clear(); for(int i = 0; i < m; i++) adj2[i].clear(); for(int i = 0; i < n-1; i++){ int a, b; cin >> a >> b; adj[a].pb(b), adj[b].pb(a); } for(int i = 1; i <= n; i++) dfs(i,-1,i); for(int i = 0; i < m; i++) vis[i]=0; cin >> m; vector<int> v; v.clear(); for(int i = 0; i < m; i++) cin >> s[i] >> t[i], v.pb(s[i]), v.pb(t[i]); sort(all(v)); v.erase(unique(all(v)),end(v)); for(int i = 0; auto u : v) ind[u]=i, dfs(u,-1,i++); for(int i = 0; i < m; i++){ for(int j = 0; j < m; j++){ if(i==j) continue; int a = s[i], b = t[i], c = s[j], d = t[j]; if(inPath(c,a,b)) adj2[j].pb(i); } } for(int i = 0; i < m; i++) if(!vis[i]) dfs2(i); cout << (!Cycle?"Yes":"No") << "\n"; } int32_t main() { ios_base::sync_with_stdio(false); cin.tie(0); int t = 1; cin >> t; while(t--) solve(); }

Compilation message (stderr)

jail.cpp: In function 'void solve()':
jail.cpp:51:17: warning: range-based 'for' loops with initializer only available with '-std=c++2a' or '-std=gnu++2a'
   51 |  for(int i = 0; auto u : v) ind[u]=i, dfs(u,-1,i++);
      |                 ^~~~
jail.cpp:55:38: warning: unused variable 'd' [-Wunused-variable]
   55 |    int a = s[i], b = t[i], c = s[j], d = t[j];
      |                                      ^
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