This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fbo find_by_order
#define ook order_of_key
typedef long long ll;
typedef pair<ll,ll> pi;
typedef vector<ll> vi;
typedef long double ld;
typedef tree<ll, null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> pbds;
typedef set<ll>::iterator sit;
typedef map<ll,ll>::iterator mit;
typedef pair<int,pair<int,int> > tri;
ll dp[2000050][2];
ll sum[4000050];
long long solve(int N, int K, int *A, int *B){
ll ans = 0;
//din pass first subject
dp[0][0] = 0;
dp[0][1] = -(ll)1e18;
sum[0] = B[0];
for(int i = 1; i < N; i++) sum[i] = sum[i-1] + (ll)B[i];
for(int i = N; i < 2 * N; i++) sum[i] = sum[N-1] + sum[i-N];
for(int i = 1; i < N; i++){
dp[i][0] = max(dp[i-1][0], dp[i-1][1]);
dp[i][1] = (ll)A[i] + max(dp[i-1][0] - (sum[i+K-1]-sum[i-1]), dp[i-1][1] - (ll)B[(i+K-1)%N]);
}
ans = max(ans, max(dp[N-1][0], dp[N-1][1]));
//pass the first subject
dp[0][1] = (ll)A[0] - sum[K-1];
dp[0][0] = -(ll)1e18;
for(int i = 0; i < K; i++) B[i] = 0;
sum[0] = B[0];
for(int i = 1; i < N; i++) sum[i] = sum[i-1] + (ll)B[i];
for(int i = N; i < 2 * N; i++) sum[i] = sum[N-1] + sum[i-N];
for(int i = 1; i < N ; i++){
dp[i][0] = max(dp[i-1][0], dp[i-1][1]);
dp[i][1] = (ll)A[i] + max(dp[i-1][0] - (sum[i+K-1]-sum[i-1]), dp[i-1][1] - (ll)B[(i+K-1)%N]);
//cout<<i<<' '<<dp[i][0]<<' '<<dp[i][1] <<endl;
}
ans = max(ans, max(dp[N-1][0], dp[N-1][1]));
return ans;
}
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