Submission #737008

# Submission time Handle Problem Language Result Execution time Memory
737008 2023-05-06T12:58:37 Z DAleksa Event Hopping (BOI22_events) C++17
0 / 100
206 ms 20372 KB
#include <bits/stdc++.h>

using namespace std;

struct seg {
    int L;
    int R;
    bool operator < (seg s) {
        if(R == s.R) return L < s.L;
        return R < s.R;
    }
};

const int N = 1e5 + 10, LOG = 18;
int n, q;
map<int, int> m;
seg a[N];
int sparse[N][LOG];
int st[8 * N];
int L[2 * N];

void build(int index, int l, int r) {
    if(l > r) return;
    if(l == r) {
        st[index] = L[l];
        return;
    }
    int mid = (l + r) / 2;
    build(2 * index + 1, l, mid);
    build(2 * index + 2, mid + 1, r);
    st[index] = min(st[2 * index + 1], st[2 * index + 2]);
}

int get(int index, int l, int r, int L, int R) {
    if(l > r || r < L || R < l) return 1e9;
    if(L <= l && r <= R) return st[index];
    int mid = (l + r) / 2;
    return min(get(2 * index + 1, l, mid, L, R), get(2 * index + 2, mid + 1, r, L, R));
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cin >> n >> q;
    vector<int> compress;
    for(int i = 0; i < n; i++) {
        cin >> a[i].L >> a[i].R;
        compress.push_back(a[i].L);
        compress.push_back(a[i].R);
    }
    sort(compress.begin(), compress.end());
    for(int i = 0; i < n; i++) {
        int oldL = a[i].L, oldR = a[i].R;
        a[i].L = lower_bound(compress.begin(), compress.end(), a[i].L) - compress.begin();
        a[i].R = lower_bound(compress.begin(), compress.end(), a[i].R) - compress.begin();
        m[oldL] = a[i].L;
        m[oldR] = a[i].R;
    }
    vector<pair<pair<int, bool>, int>> v;
    for(int i = 0; i < n; i++) {
        v.push_back({{a[i].L, false}, i});
        v.push_back({{a[i].R, true}, i});
    }
    sort(v.begin(), v.end());
    int mx = 0;
    for(int i = 0; i < v.size(); i++) {
        if(v[i].first.second) {
            if(a[v[i].second].R == a[mx].R) sparse[v[i].second][0] = -1;
            else sparse[v[i].second][0] = mx;
        } else {
            if(a[mx].R < a[v[i].second].R) mx = v[i].second;
        }
    }
    for(int j = 1; j < LOG; j++) {
        for(int i = 0; i < n; i++) {
            if(sparse[i][j - 1] == -1) sparse[i][j] = -1;
            else sparse[i][j] = sparse[sparse[i][j - 1]][j - 1];
        }
    }
    for(int i = 0; i < 2 * N; i++) L[i] = 1e9;
    for(int i = 0; i < n; i++) L[a[i].R] = min(L[a[i].R], a[i].L);
    build(0, 0, 2 * n);
    while(q--) {
        int s, e;
        cin >> s >> e;
        s--;
        e--;
        if(s == e) {
            cout << "0\n";
            continue;
        }
        if(a[s].R > a[e].R) {
            cout << "impossible\n";
            continue;
        }
        if(a[s].R >= a[e].L) {
            cout << "1\n";
            continue;
        }
        int res = 0;
        for(int j = LOG - 1; j >= 0; j--) {
            if(sparse[s][j] == -1) continue;
            if(a[sparse[s][j]].R >= a[e].L) continue;
            s = sparse[s][j];
            res += (1 << j);
        }
        int have = get(0, 0, 2 * n, a[e].L, a[e].R);
        if(have <= a[s].R) cout << res + 2 << "\n";
        else cout << "impossible\n";
    }
    return 0;
}

/*
OBS: uvek cu uzimati segment sa najdaljim endom (osim u poslednjem koraku mozda)
0. (mozda kompresija)
1. Za svaki segment nadjem onaj sa najdaljim endom u koji moze da udje (stavim sve u jedan vector, dodajem ih, svaki put kad dodjem do
    do enda, nadjem najveci aktivni end)
2. Izbuildujem sparse tabelu nad tim
3. Query: vidim koliko koraka mi treba da dodjem do <=end
    -ako sam >=start, ispisem, kraj
    -u suprotnom, gledam da li postoji segment sa startom <=gde sam, i endom u zavrsnom intervalu (segmentno nad endovima, rmq), kraj
*/

/*
5 1
1 2
2 3
3 5
4 5
5 6
1 5
*/

Compilation message

events.cpp: In function 'int main()':
events.cpp:66:22: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::pair<std::pair<int, bool>, int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   66 |     for(int i = 0; i < v.size(); i++) {
      |                    ~~^~~~~~~~~~
# Verdict Execution time Memory Grader output
1 Correct 1 ms 1108 KB Output is correct
2 Incorrect 188 ms 20348 KB Output isn't correct
3 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Correct 1 ms 1108 KB Output is correct
2 Correct 1 ms 1108 KB Output is correct
3 Incorrect 2 ms 1236 KB Output isn't correct
4 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Correct 1 ms 1108 KB Output is correct
2 Correct 1 ms 1108 KB Output is correct
3 Incorrect 2 ms 1236 KB Output isn't correct
4 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Correct 1 ms 1108 KB Output is correct
2 Correct 1 ms 1108 KB Output is correct
3 Incorrect 2 ms 1236 KB Output isn't correct
4 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Incorrect 206 ms 20372 KB Output isn't correct
2 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Correct 1 ms 1108 KB Output is correct
2 Incorrect 188 ms 20348 KB Output isn't correct
3 Halted 0 ms 0 KB -