Submission #735044

#	Time	Username	Problem	Language	Result	Execution time	Memory
735044		snowman	Stove (JOI18_stove)	C++17	0 / 100	1 ms	324 KiB

stove

#include <bits/stdc++.h>
//Soltan Cristian
#define fri(a, b) for (int i = (a); i < (b); ++i)
#define frj(a, b) for(int j = a; j < b; j++)
#define frk(a, b) for(int k = a; k < b; k++)
#define frm(a, b, i) for(int i = b; i >= a; i--)
#define ll long long
#define all(x) x.begin(), x.end()
#define mod 1000000007
#define pb push_back
#define st first
#define nd second
#define sz(x) (ll)x.size()
#define rall(x) x.rbegin(), x.rend()
#define ct(x) cout << x
#define cts(x) cout << x << ' '
#define ctn(x) cout << x << '\n'
#define Y cout << "YES" << '\n'
#define N cout << "NO" << '\n'
using namespace std;
using vi = vector<int>;
using vl = vector<ll>;
using vs = vector<string>;
using vb = vector<bool>;
using ml = map<ll, ll>;
using vii = vector<vector<int>>;
using vll = vector<vector<ll>>;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
const int dx[] = {-1, 0, 1, 0};
const int dy[] = {0, 1, 0, -1};
template <typename T>void read(T n, vector<T> &a){fri(0, n){cin >> a[i];}}
template<typename T>void print(T n, T m, vector<vector<T>> &dp){fri(0, n){ct('\n');frj(0, m){ct(setw(5));cts(dp[i][j]);}}}



const int mxa = 1e9 + 1;
// string __fname = "exclusiv";  
// ifstream in(__fname + ".in"); 
// ofstream out (__fname + ".out"); 
// #define cin in 
// #define cout out


void solve(){
	int n, k;
    cin >> n >> k;
    vi a(n);
    fri(0, n){
        cin >> a[i];
    }
    vii dp(n + 1, vi(k + 1));
    dp[1][1] = 1;
    fri(2, n + 1){
        dp[i][1] = a[i - 1] - a[0] + 1; 
    }
    fri(2, n + 1){
        frj(2, k + 1){
            dp[i][j] = min(dp[i - 1][j - 1] + 1, dp[i- 1][j] + a[i - 1] - a[i - 2]);
        }
    }
    cout << dp[n][k] << '\n';

}


int main()
{   
    ios_base::sync_with_stdio(0); cin.tie(0); ct(fixed); ct(setprecision(10)); 
    // int t;
    // cin >> t;
    // while(t--)
        solve();
    return 0;
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 30
• Subtask 3: 0 / 50