//by szh
#include<bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define pii pair<int,int>
#define pll pair<long long,long long>
#define pb push_back
#define debug(x) cerr<<#x<<"="<<x<<endl
#define pq priority_queue
#define inf 0x3f
#define rep(i,a,b) for (int i=a;i<(b);i++)
#define MP make_pair
#define SZ(x) (int(x.size()))
#define ll long long
#define mod 1000000007
#define ALL(x) x.begin(),x.end()
void inc(int &a,int b) {a=(a+b)%mod;}
void dec(int &a,int b) {a=(a-b+mod)%mod;}
int lowbit(int x) {return x&(-x);}
ll p0w(ll base,ll p) {ll ret=1;while(p>0){if (p%2ll==1ll) ret=ret*base%mod;base=base*base%mod;p/=2ll;}return ret;}
const int maxn = 2e5+10;
int n,d,T;
int t[maxn];
int le[maxn];
int mn[maxn][20];
int lg[maxn];
int query(int l,int r) {
int tmp = lg[r-l+1];
return min(mn[l][tmp],mn[r-(1<<tmp)+1][tmp]);
}
pair<ll,int> tree[maxn*4],add[maxn*4];
void update(int c,int cl,int cr,int l,int r,ll val1,int val2) {
if (l<=cl and cr<=r) {
tree[c].fi += val1;
tree[c].se += val2;
add[c].fi += val1;
add[c].se += val2;
return;
}
int mid=cl+cr>>1;
if (add[c]!=MP(0ll,0)) {
tree[c<<1].fi += add[c].fi;
tree[c<<1|1].fi += add[c].fi;
tree[c<<1].se += add[c].se;
tree[c<<1|1].se += add[c].se;
add[c<<1].fi += add[c].fi, add[c<<1|1].fi += add[c].fi;
add[c<<1].se += add[c].se, add[c<<1|1].se += add[c].se;
add[c] = {0ll,0};
}
if (l<=mid) update(c<<1,cl,mid,l,r,val1,val2);
if (r>mid) update(c<<1|1,mid+1,cr,l,r,val1,val2);
tree[c] = tree[c<<1];
if (tree[c<<1|1].fi>tree[c].fi or (tree[c<<1|1].fi==tree[c].fi and tree[c<<1|1].se<tree[c].se)) tree[c] = tree[c<<1|1];
return;
}
pair<ll,int> solve(int cost) {
//the cost of installing each wall is cost
rep(i,1,maxn*4) tree[i] = {- 1e18,0},add[i] = {0,0};
update(1,0,n-1,0,0,1e18 + (le[0]!=maxn),0);
rep(i,1,n) {
//install a wall here
pair<ll,int> tmp = {tree[1].fi - cost,tree[1].se+1};
update(1,0,n-1,i,i,1e18 + tmp.fi,tmp.se);
if (le[i]<=i) update(1,0,n-1,le[i],i,1,0);
}
return tree[1];
}
int main() {
// freopen("input.txt","r",stdin);
std::ios::sync_with_stdio(false);cin.tie(0);
cin>>n>>d>>T;
rep(i,0,n) cin>>t[i],mn[i][0] = t[i]-i;
lg[1] = 0;
rep(i,2,maxn) lg[i] = lg[i/2]+1;
for (int i = n-1;i>=0;i--)
rep(j,1,20) {
if (i+(1<<j)>n) break;
mn[i][j] = min(mn[i][j-1],mn[i+(1<<(j-1))][j-1]);
}
rep(i,0,n) {
if (t[i]<=T) le[i] = maxn;
else {
int l = 0,r=i;
while (l<r) {
int mid = l+r>>1;
if (mid==i or query(mid,i-1)+i>T) r=mid;
else l = mid+1;
}
le[i] = l;
}
}
//monge
int l = 0, r = n;
pair<ll,int> ans;
while (l<r) {
int mid=l+r>>1;
ans = solve(mid);
if (ans.se<=d) r = mid;
else l = mid+1;//penalty too small
}
cout<<n-(ans.fi+ans.se*r);
return 0;
}
