oj.uz

Submission #730457

# Submission time Handle Problem Language Result Execution time Memory
730457 2023-04-26T00:32:55 Z n0sk1ll Amusement Park (JOI17_amusement_park) C++17
0 / 100
 22 ms 3168 KB 
#include <bits/stdc++.h>

#define FAST ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);cerr.tie(0)
#define mp make_pair
#define xx first
#define yy second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define all(x) x.begin(),x.end()
#define ff(i,a,b) for (int i = a; i < b; i++)
#define fff(i,a,b) for (int i = a; i <= b; i++)
#define bff(i,a,b) for (int i = b-1; i >= a; i--)
#define bfff(i,a,b) for (int i = b; i >= a; i--)

using namespace std;
long double typedef ld;
unsigned int typedef ui;
long long int typedef li;
pair<int,int> typedef pii;
pair<li,li> typedef pli;
pair<ld,ld> typedef pld;
vector<vector<int>> typedef graph;
unsigned long long int typedef ull;
//const int mod = 998244353;
const int mod = 1000000007;







//Note to self: Check for overflow

#include "Joi.h"

namespace joi
{
    int up[10004];

    int Up(int x)
    {
        if (up[x]<0) return x;
        return up[x]=Up(up[x]);
    }

    void build(int n)
    {
        ff(i,0,n) up[i]=-1;
    }

    bool dsu(int a, int b)
    {
        a=Up(a),b=Up(b);
        if (a==b) return false;
        if (up[a]<up[b]) swap(a,b);
        up[b]+=up[a],up[a]=b;
        return true;
    }

    bool broj[60];
    graph g(10004);
    int tb=0;

    void dfs(int p, int q)
    {
        MessageBoard(p,broj[tb++]);
        if (tb==60) tb=0;

        for (auto it : g[p]) if (it!=q) dfs(it,p);
    }

    void solve(int n, int m, int A[], int B[], li x)
    {
        build(n);
        ff(i,0,m) if (dsu(A[i],B[i])) g[A[i]].pb(B[i]),g[B[i]].pb(A[i]);

        ff(i,0,60) broj[i]=((x>>i)&1);

        dfs(0,-1);
    }
}

using namespace joi;

void Joi(int N, int M, int A[], int B[], long long X, int T)
{
    solve(N,M,A,B,X);
}

#include <bits/stdc++.h>

#define FAST ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);cerr.tie(0)
#define mp make_pair
#define xx first
#define yy second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define all(x) x.begin(),x.end()
#define ff(i,a,b) for (int i = a; i < b; i++)
#define fff(i,a,b) for (int i = a; i <= b; i++)
#define bff(i,a,b) for (int i = b-1; i >= a; i--)
#define bfff(i,a,b) for (int i = b; i >= a; i--)

using namespace std;
long double typedef ld;
unsigned int typedef ui;
long long int typedef li;
pair<int,int> typedef pii;
pair<li,li> typedef pli;
pair<ld,ld> typedef pld;
vector<vector<int>> typedef graph;
unsigned long long int typedef ull;
//const int mod = 998244353;
const int mod = 1000000007;







//Note to self: Check for overflow

#include "Ioi.h"

namespace ioi
{
    int up[10004];

    int Up(int x)
    {
        if (up[x]<0) return x;
        return up[x]=Up(up[x]);
    }

    void build(int n)
    {
        ff(i,0,n) up[i]=-1;
    }

    bool dsu(int a, int b)
    {
        a=Up(a),b=Up(b);
        if (a==b) return false;
        if (up[a]<up[b]) swap(a,b);
        up[b]+=up[a],up[a]=b;
        return true;
    }

    bool broj[60];
    graph g(10004);
    bool boja[10004];
    int tb=0;

    void dfs(int p, int q)
    {
        boja[p]=tb;
        if (tb==60) tb=0;

        for (auto it : g[p]) if (it!=q) dfs(it,p);
    }

    bool uklj[69];
    int kolko=0;
    li ans=0;

    void klizaj(int p, int q)
    {
        if (kolko==60) return;
      	int sta=0;
        //int sta=Move(p);
        if (!uklj[boja[p]])
        {
            uklj[boja[p]]=1,kolko++;
            if (sta) ans|=(1ll<<boja[p]);
        }
        if (kolko==60) return;

        //for (auto it : g[p]) if (it!=q) klizaj(it,p);
        if (kolko==60) return;

        //if (q!=-1) Move(q);
    }

    li solve(int n, int m, int A[], int B[], int P, int V)
    {
        build(n);
        ff(i,0,m) if (dsu(A[i],B[i])) g[A[i]].pb(B[i]),g[B[i]].pb(A[i]);

        dfs(0,-1);

        uklj[boja[P]]=1,kolko++;
        if (V) ans|=(1ll<<boja[P]);

        for (auto it : g[P]) klizaj(it,P);
        return ans;
    }
}

using namespace ioi;

long long Ioi(int N, int M, int A[], int B[], int P, int V, int T)
{
    return solve(N,M,A,B,P,V);
}

Subtask #1
0 / 8.0

# Verdict Execution time Memory Grader output
1 Incorrect 1 ms 1044 KB Wrong Answer [7]
2 Halted 0 ms 0 KB -

Subtask #2
0 / 10.0

# Verdict Execution time Memory Grader output
1 Incorrect 22 ms 3132 KB Wrong Answer [7]
2 Halted 0 ms 0 KB -

Subtask #3
0 / 10.0

# Verdict Execution time Memory Grader output
1 Incorrect 0 ms 1044 KB Wrong Answer [7]
2 Halted 0 ms 0 KB -

Subtask #4
0 / 55.0

# Verdict Execution time Memory Grader output
1 Incorrect 19 ms 3084 KB Wrong Answer [7]
2 Halted 0 ms 0 KB -

Subtask #5
0 / 17.0

# Verdict Execution time Memory Grader output
1 Incorrect 22 ms 3168 KB Wrong Answer [7]
2 Halted 0 ms 0 KB -