This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "boxes.h"
#include <bits/stdc++.h>
#define nmax 10000008
const long long inf = 1e18;
using namespace std;
int n, k, l, pl, pr, pmid, cnt = 0;
long long res, ans;
struct container{
long long cur, sz, sum[nmax];
void insert(int x){
sz++;
cur--;
if (cur < 0)
cur += k;
sum[cur] += x;
}
void erase(int x){
sum[cur] -= x;
cur++;
if (cur >= k)
cur -= k;
sz--;
}
long long cost(){
return sum[cur] * 2;
}
}u, v;
vector<int>vtu, vtv;
stack<int>s;
long long delivery(int N, int K, int L, int p[]) {
ans = inf;
cnt = n = N;
k = K;
l = L;
if (l % 2 == 0)
pmid = l / 2;
else
pmid = -1;
for (int i = 0; i < n && p[i] < l - p[i]; i++){
u.insert(p[i]);
vtu.push_back(p[i]);
cnt--;
}
for (int i = n - 1; i >= 0 && p[i] > l - p[i]; i--){
v.insert(l - p[i]);
vtv.push_back(l - p[i]);
cnt--;
}
if (pl - pr == 1)
return u.cost() + v.cost();
int r = (k - (cnt % k)) % k;
res = 1LL * n * (cnt / k);
if (!r)
return res + u.cost() + v.cost();
for (int i = 1; i <= r; i++){
u.erase(vtu.back());
s.push(vtu.back());
vtu.pop_back();
}
ans = min(ans, res + u.cost() + v.cost());
for (int i = 1; i <= r; i++){
u.insert(s.top());
s.pop();
v.erase(vtv.back());
ans = min(ans, res + u.cost() + v.cost());
}
return res;
}
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