This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#pragma GCC optimize ("Ofast", "unroll-loops")
using namespace std;
#define ll long long
#define int ll
#define FOR(i,a,b) for (int i = (a); i<(b); i++)
#define REP(i,n) FOR(i,0,n)
#define REP1(i,n) FOR(i,1,n+1)
#define RREP(i,n) for (int i=(n)-1; i>=0; i--)
#define f first
#define s second
#define pb push_back
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)(x.size())
#define SQ(x) (x)*(x)
#define pii pair<int, int>
#define pip pair<int, pii>
#define pdd pair<double ,double>
#define pcc pair<char, char>
#define endl '\n'
//#define TOAD
#ifdef TOAD
#define bug(x) cerr<<__LINE__<<": "<<#x<<" is "<<x<<endl
#define IOS()
#else
#define bug(...)
#define IOS() ios::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#endif
const ll inf = 1ll<<60;
const ll iinf = 2147483647;
const ll mod = 1e9+7;
const ll maxn=2e5+5;
const ll maxm=105;
const double PI=acos(-1);
ll pw(ll x, ll p, ll m=mod){
ll ret=1;
while (p>0){
if (p&1){
ret*=x;
ret%=m;
}
x*=x;
x%=m;
p>>=1;
}
return ret;
}
ll inv(ll a, ll m=mod){
return pw(a,m-2,m);
}
int n, k, c;
struct pp{
int arr[6];
};
struct tup{
int val;
vector<pp> cho; // size k
int cid;
bool operator < (const tup &b)const{
return val<b.val;
}
};
pair<int, vector<pp>> opt(vector<pp> &cur){
pair<int, vector<pp>> ret;
vector<bool> occ(SZ(cur));
ret.f = 0;
REP(i, k){
pii mx = {-1, -1};
int rmx = 0;
REP(j, SZ(cur)){
rmx = max(rmx, cur[j].arr[i]);
if (!occ[j] && cur[j].arr[i]>mx.f){
mx.f = cur[j].arr[i];
mx.s = j;
}
}
//assert(mx.s != -1);
ret.f+=rmx;
ret.s.pb(cur[mx.s]);
occ[mx.s] = 1;
}
REP(i, SZ(cur)){
if (!occ[i]) ret.s.pb(cur[i]);
}
return ret;
}
signed main(){
IOS();
cin>>n>>k>>c;
priority_queue<tup> pq;
vector<pp> vc(n);
REP(i, n) {
REP(j, k) {
cin>>vc[i].arr[j];
}
}
pair<int, vector<pp> > a = opt(vc);
pq.push({a.f, a.s, -1});
tup tp;
while(c--){
tp = pq.top(); pq.pop();
// cout<<tp.val<<' '<<tp.cho.size()<<' '<<tp.cid<<endl;
if (k == SZ(tp.cho)){
continue; // done
}
FOR(i, tp.cid+1, k){
tup tmp = tp;
tmp.cid = i-1;
tmp.cho.erase(tmp.cho.begin()+i);
pair<int, vector<pp> > aa = opt(tmp.cho);
tmp.val = aa.f; tmp.cho = aa.s;
pq.push(tmp);
}
}
cout<<tp.val<<endl;
}
/*
5
1 2 1 2 2
6
2 4
*/
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