Submission #726045

#TimeUsernameProblemLanguageResultExecution timeMemory
726045JohannGraph (BOI20_graph)C++14
17 / 100
1072 ms328 KiB
#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef vector<int> vi; typedef vector<vi> vvi; typedef vector<pii> vpii; typedef vector<vpii> vvpii; int N, M; vvpii adj; vi vis; vpii poly; vi newNodes; vector<int> ans; bool possible = true; bool xdefined = false; int x = 0; void dfs(int v) { vis[v] = true; newNodes.push_back(v); int u, c; for (pii e : adj[v]) { tie(u, c) = e; if (vis[u]) { // check whether cohrerent possible pii res = {poly[v].first + poly[u].first, poly[v].second + poly[u].second}; if (res.first == c && res.second == 0) { // perfect, nothing to do } else if (xdefined) { if (res.first + res.second * x - c != 0) possible = false; } else { // not x defined if (res.second == 0) possible = false; else { xdefined = true; assert((c - res.first) % res.second == 0); x = (c - res.first) / res.second; } } } else { // new Node poly[u] = {c - poly[v].first, -poly[v].second}; dfs(u); } } } ll eval(int xcand) { ll tmpAns = 0; for (int u : newNodes) tmpAns += (ll)abs(poly[u].first + poly[u].second * xcand); return tmpAns; } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> N >> M; adj.resize(N); for (int i = 0, a, b, c; i < M; ++i) { cin >> a >> b >> c; --a, --b, c *= 2; adj[a].push_back({b, c}), adj[b].push_back({a, c}); } vis.assign(N, false); ans.resize(N); poly.resize(N); for (int v = 0; v < N; ++v) if (!vis[v]) { xdefined = false; x = 0; poly[v] = {0, 1}; newNodes.clear(); dfs(v); if (!xdefined) { int l = 0, r = 0; for (int w : newNodes) if (poly[w].second != 0) { int xcand = -poly[w].first / poly[w].second; l = min(l, xcand), r = max(r, xcand); } while (l < r) { int m = (l + r) / 2; ll e1 = eval(m); ll e2 = eval(m + 1); if (e1 < e2) r = m; else if (e1 > e2) l = m + 1; else l = r = m; } x = l; } for (int u : newNodes) ans[u] = poly[u].first + poly[u].second * x; } if (possible) { cout << "YES\n"; for (int v = 0; v < N; ++v) cout << ans[v] / (double)2 << " "; cout << "\n"; } else { cout << "NO\n"; } return 0; }
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