Submission #725141

#TimeUsernameProblemLanguageResultExecution timeMemory
725141n0sk1llPainting Walls (APIO20_paint)C++14
100 / 100
1057 ms266888 KiB
#include <bits/stdc++.h>

#define FAST ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);cerr.tie(0)
#define mp make_pair
#define xx first
#define yy second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define all(x) x.begin(),x.end()
#define ff(i,a,b) for (int i = a; i < b; i++)
#define fff(i,a,b) for (int i = a; i <= b; i++)
#define bff(i,a,b) for (int i = b-1; i >= a; i--)
#define bfff(i,a,b) for (int i = b; i >= a; i--)

using namespace std;
long double typedef ld;
unsigned int typedef ui;
long long int typedef li;
pair<int,int> typedef pii;
pair<li,li> typedef pli;
pair<ld,ld> typedef pld;
vector<vector<int>> typedef graph;
unsigned long long int typedef ull;
//const int mod = 998244353;
const int mod = 1000000007;







//Note to self: Check for overflow

#include "paint.h"

int upizdi(int i, int n)
{
    i%=n;
    if (i<0) i+=n;
    return i;
}

vector<int> koji[100005]; //koji kontraktori sadrze ovu boju, svkk su indexirani

vector<int> poz[100005]; //reindeksirane kontrakcije

bool chiba[100005]; //da li siba, na osnovu toga racuna minimalan broj poteza

int minimumInstructions(int n, int m, int k, vector<int> c, vector<int> a, vector<vector<int>> b)
{
    ff(i,0,m) for (auto it : b[i]) koji[it].pb(i);
    ff(i,0,n) for (auto kont : koji[c[i]]) poz[upizdi(kont-i,m)].pb(i);

    ff(i,0,m)
    {
        int uzo=1;
        if (uzo>=m) chiba[poz[i][0]-m+1]=1;
        ff(j,1,(int)poz[i].size())
        {
            if (poz[i][j]-poz[i][j-1]==1) uzo++;
            else uzo=1;

            if (uzo>=m) chiba[poz[i][j]-m+1]=1;
        }
    }

    int poslednji=-mod,snaga=0,ans=0;
    ff(i,0,n)
    {
        if (chiba[i]) poslednji=i;
        if (snaga<=0)
        {
            if (i>=poslednji+m) return -1;
            snaga=poslednji+m-i,ans++;
        }
        snaga--;
    }

    return ans;
}

//Note to self: Check for overflow

/*

8 3 5
3 3 1 3 4 4 2 2
3 0 1 2
2 2 3
2 3 4

*/

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