This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#define here cerr<<"===========================================\n"
#define dbg(x) cerr<<#x<<": "<<x<<endl;
#include <bits/stdc++.h>
#define ld double
#define ll long long
#define ull unsigned long long
#define llinf 100000000000000000LL // 10^17
#define iinf 2000000000 // 2*10^9
#define pb push_back
#define popb pop_back
#define fi first
#define sc second
#define endl '\n'
#define pii pair<int,int>
#define pll pair<ll,ll>
#define pld pair<ld,ld>
#define all(a) a.begin(),a.end()
using namespace std;
#define mod 1000000007
#define maxn 200005
ll fact[maxn];
ll add(ll x,ll y){
x+=y;
if(x<0){
x%=mod;
x+=mod;
}else{
if(x>=mod) x%=mod;
}
return x;
}
ll mul(ll a,ll b){
ll ans = (a*b)%mod;
if(ans<0) ans+=mod;
return ans;
}
ll po(ll x,ll y){
if(y==0) return 1LL;
ll ans = po(x,y/2);
ans = mul(ans,ans);
if(y&1) ans = mul(ans,x);
return ans;
}
ll inv(ll x){return po(x,mod-2);}
ll ch(ll n,ll k){
if(k>n) return 0;
ll ans = fact[n];
ans = mul(ans,inv(fact[k]));
ans = mul(ans,inv(fact[n-k]));
return ans;
}
ll n,k;
ll a[maxn];
ll ask[maxn];
ll rez[maxn];
ll cntl[maxn],cntr[maxn];
vector<pll> v[maxn];
void tc(){
ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);
fact[0] = 1;
for(ll i = 1;i<maxn;i++) fact[i] = mul(fact[i-1],i);
cin >> n >> k;
for(ll i = 1;i<=n;i++) cin >> a[i];
ll ans = 1;
stack<ll> st;
for(ll i = n;i>=1;i--){
while(st.size()&&st.top()>a[i]){
cntr[st.top()]--;
v[i].pb({st.top(),1});
st.pop();
}
cntr[a[i]]++;
v[i].pb({a[i],-1});
st.push(a[i]);
}
while(st.size()) st.pop();
for(ll i = 1;i<=n;i++){
for(pll p : v[i]){
ll x = p.fi;
ll d = p.sc;
ans = mul(ans,inv(ch(cntr[x]+cntl[x],cntl[x])));
cntr[x]+=d;
ans = mul(ans,ch(cntr[x]+cntl[x],cntl[x]));
}
rez[i] = ans;
while(st.size()&&st.top()>a[i]){
ll x = st.top();
ans = mul(ans,inv(ch(cntr[x]+cntl[x],cntl[x])));
cntl[x]--;
ans = mul(ans,ch(cntr[x]+cntl[x],cntl[x]));
st.pop();
}
ll x = a[i];
ans = mul(ans,inv(ch(cntr[x]+cntl[x],cntl[x])));
cntl[x]++;
ans = mul(ans,ch(cntr[x]+cntl[x],cntl[x]));
st.push(a[i]);
}
for(ll i = 1;i<=k;i++){
ll x; cin >> x;
cout<<rez[x]<<endl;
}
}
int main(){
ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);
int t; t = 1;
while(t--){
tc();
}
return 0;
}
/**
5 2
3 5 1 4 3
3 5
**/
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