Submission #723429

#	Time	Username	Problem	Language	Result	Execution time	Memory
723429		n0sk1ll	Koala Game (APIO17_koala)	C++14	19 / 100	15 ms	320 KiB

koala

#include <bits/stdc++.h>

#define FAST ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);cerr.tie(0)
#define mp make_pair
#define xx first
#define yy second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define all(x) x.begin(),x.end()
#define ff(i,a,b) for (int i = a; i < b; i++)
#define fff(i,a,b) for (int i = a; i <= b; i++)
#define bff(i,a,b) for (int i = b-1; i >= a; i--)
#define bfff(i,a,b) for (int i = b; i >= a; i--)

using namespace std;
long double typedef ld;
unsigned int typedef ui;
long long int typedef li;
pair<int,int> typedef pii;
pair<li,li> typedef pli;
pair<ld,ld> typedef pld;
vector<vector<int>> typedef graph;
unsigned long long int typedef ull;
//const int mod = 998244353;
const int mod = 1000000007;







//Note to self: Check for overflow

#include "koala.h"

int R[100];
int B[100];

int minValue(int n, int w)
{
    B[0]=1;
    playRound(B,R);
    ff(i,0,n) if (R[i]==0) return i;
    return 0;
}

int maxValue(int n, int w)
{
    ff(i,0,n) B[i]=1;
    int keci=n;

    while (keci>1)
    {
        playRound(B,R);
        ff(i,0,n)
        {
            if (R[i]==0)
            {
                if (B[i]>0) keci--;
                B[i]=0;
            }
        }
        ff(i,0,n)
        {
            if (R[i]!=0 && B[i]!=0)
            {
                B[i]=w/keci;
            }
        }
    }

    ff(i,0,n) if (B[i]>0) return i;

    return 0;
}

///

int greaterValue(int N, int W)
{
    // TODO: Implement Subtask 3 solution here.
    // You may leave this function unmodified if you are not attempting this
    // subtask.
    return 0;
}

void allValues(int N, int W, int *P)
{
    if (W == 2*N)
    {
        // TODO: Implement Subtask 4 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    } else
    {
        // TODO: Implement Subtask 5 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    }
}

• Subtask 1: 4 / 4
• Subtask 2: 15 / 15
• Subtask 3: 0 / 18
• Subtask 4: 0 / 10
• Subtask 5: 0 / 53