This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pii pair<int, int>
#define vb vector<bool>
#define vi vector<int>
#define vpii vector<pii>
#define vvb vector<vb>
#define vvi vector<vi>
#define vvpii vector<vpii>
#define sz(x) (int)(x).size()
#define all(x) (x).begin(), (x).end()
int N, D, T;
vi P;
vi protest; // state: 0 : never, 1 : save, -1 : changable
vi trigger; // the rightmost prisoner to trigger [i], only for -1
vvi adj; // graph
vi par; // parent
vpii maxSubtree;
pii NONE_PAIR = {-1, -1};
vvi nodeByLen; // nodes by their depth
void dfs(int v)
{
if (maxSubtree[v] == NONE_PAIR)
{
if (sz(adj[v]) == 0)
{
maxSubtree[v] = {0, v};
return;
}
for (int u : adj[v])
dfs(u);
for (int u : adj[v])
maxSubtree[v] = max(maxSubtree[v], maxSubtree[u]);
++maxSubtree[v].first;
}
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> N >> D >> T;
D = min(D, N);
P.resize(N);
for (int i = 0; i < N; ++i)
cin >> P[i];
protest.assign(N, 0);
trigger.assign(N, -1);
stack<pii> blockers; // which range is blocked [i, j] inclusive
for (int i = 0; i < N; ++i)
{
if (P[i] <= T)
{
protest[i] = 1;
blockers.push({i, min(i + T - P[i], N)});
}
else
{
while (!blockers.empty() && blockers.top().second < i)
blockers.pop();
if (!blockers.empty())
protest[i] = -1, trigger[i] = blockers.top().first;
}
}
adj.resize(N);
par.assign(N, -1);
stack<int> todo;
for (int i = N - 1; i >= 0; --i)
{
if (protest[i] != -1)
continue;
while (!todo.empty() && trigger[todo.top()] > i)
todo.pop();
if (!todo.empty())
adj[todo.top()].push_back(i), par[i] = todo.top();
todo.push(i);
}
maxSubtree.assign(N, NONE_PAIR);
nodeByLen.resize(N);
for (int i = 0; i < N; ++i)
if (protest[i] == -1)
{
if (maxSubtree[i] == NONE_PAIR)
dfs(i);
nodeByLen[maxSubtree[i].first].push_back(i);
}
int idx = N - 1;
while (D > 0 && idx >= 0)
{
if (sz(nodeByLen[idx]) == 0)
{
--idx;
}
else
{
int v = nodeByLen[idx].back();
nodeByLen[idx].pop_back();
if (protest[v] == -1)
{
--D;
int u = maxSubtree[v].second;
while (u != -1)
{
protest[u] = 0;
u = par[u];
}
}
}
}
int ans = 0;
for (int x : protest)
if (x == -1 || x == 1)
++ans;
cout << ans << endl;
return 0;
}
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