Submission #718842

# Submission time Handle Problem Language Result Execution time Memory
718842 2023-04-05T00:59:43 Z Ozy Harbingers (CEOI09_harbingers) C++17
100 / 100
225 ms 29832 KB
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
#define debug(a) cout << #a << " = " << a << endl
#define debugsl(a) cout << #a << " = " << a << ", "
#define rep(i,a,b) for(int i = (a); i <= (b); i++)
#define repa(i,a,b) for(int i = (a); i >= (b); i--)
#define lli long long int
#define pll pair<lli,lli>

#define MAX 100000
// para los hijos
#define des first
#define w second
//para el arreglo de lin
#define prep first
#define vel second
//para el convex hull
#define m first
#define ord second

lli n,a,b,c;
vector<pll> hijos[MAX+2];
pll lin[MAX+2],ch[MAX+2];
long double anterior[MAX+2];
int ancestros[MAX+2][20];
lli dp[MAX+2],prof[MAX+2],rp[MAX+2];

long double cruce(pll a, pll b) {
    long double u = a.ord - b.ord;
    long double v = b.m - a.m;
    u /= v;
    return u;
}

void solve(lli pos, lli padre, lli p) {

    prof[pos] = p;

    // responde la pregunta para mi posicion
    lli x = padre;
    repa(i,18,0) if (anterior[ancestros[x][i]] > (long double)lin[pos].vel) x = ancestros[x][i];
    if (anterior[x] > (long double)lin[pos].vel) x = ancestros[x][0];
    dp[pos] = lin[pos].prep + prof[pos]*lin[pos].vel + dp[x] - prof[x]*lin[pos].vel;

    //hago mi propia línea
    ch[pos].ord = dp[pos];
    ch[pos].m = -prof[pos];

    //me integro en el convex hull trick
    x = padre;
    repa(i,18,0) if (cruce(ch[pos], ch[ancestros[x][i]]) < anterior[ancestros[x][i]]) x = ancestros[x][i];
    if (cruce(ch[pos], ch[x]) < anterior[x]) x = ancestros[x][0];

    ancestros[pos][0] = x;
    anterior[pos] = cruce(ch[pos], ch[x]);
    rep(i,1,18) {
        ancestros[pos][i] = ancestros[x][i-1];
        x = ancestros[pos][i];
    }

    for(auto h : hijos[pos]) {
        if (h.des == rp[pos]) continue;
        rp[h.des] = pos;
        solve(h.des,pos,p+h.w);
    }

}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);

    cin >> n;
    rep(i,2,n) {
        cin >> a >> b >> c;
        hijos[a].push_back({b,c});
        hijos[b].push_back({a,c});
    }
    rep(i,2,n) cin >> lin[i].prep >> lin[i].vel;

    for (auto h : hijos[1]) {
        rp[h.des] = 1;
        solve(h.des,0,h.w);
    }

    rep(i,2,n) cout << dp[i] << ' ';

    return 0;
}
# Verdict Execution time Memory Grader output
1 Correct 1 ms 2644 KB Output is correct
2 Correct 4 ms 3412 KB Output is correct
3 Correct 65 ms 13772 KB Output is correct
4 Correct 107 ms 19176 KB Output is correct
5 Correct 119 ms 24524 KB Output is correct
6 Correct 169 ms 29832 KB Output is correct
7 Correct 92 ms 18776 KB Output is correct
8 Correct 225 ms 26580 KB Output is correct
9 Correct 203 ms 27480 KB Output is correct
10 Correct 178 ms 26472 KB Output is correct