Submission #717202

#	Time	Username	Problem	Language	Result	Execution time	Memory
717202		PanosPask	Global Warming (CEOI18_glo)	C++14	0 / 100	54 ms	2528 KiB

glo

#include <bits/stdc++.h>
#define MAXN 200000

using namespace std;

int n, x;
int a[MAXN + 2];

vector<int> dp;

int inc_lis[MAXN + 2];
int dec_lis[MAXN + 2];
bool cont[MAXN + 2];

int main(void)
{
    scanf("%d %d", &n, &x);
    for (int i = 1; i <= n; i++) {
        scanf("%d", &a[i]);
    }
    dp.resize(n + 1);

    for (int i = 0; i < n + 1; i++) {
        dp[i] = INT_MAX;
    }
    dp[0] = INT_MIN;
    for (int i = 1; i <= n; i++) {
        int curval = a[i];

        int l = 0;
        int r = n;
        while (r > l + 1) {
            int mid = (l + r) / 2;
            if (dp[mid] < curval)
                l = mid;
            else 
                r = mid;
        }

        dp[l+1] = curval;
        inc_lis[i] = l+1;
    }

    int ans = 0;

    // Find decreasing subsequence of reverse array and simultaneously check answers
    for (int i = 0; i <= n; i++)
        dp[i] = INT_MAX;
    dp[n] = INT_MIN;

    for (int i = n; i > 0; i--) {
        // Check answers
        int curval = a[i];
        int rev_val = (upper_bound(dp.rbegin(), dp.rend(), curval - x) - dp.rbegin());

        ans = max(ans, rev_val + inc_lis[i]);

        int l = 0;
        int r = n;
        while (r > l + 1) {
            int mid = (l + r) / 2;
            if (dp[mid] > curval)
                l = mid;
            else 
                r = mid;
        }

        dp[r-1] = curval;
    }

    printf("%d\n", ans);
    return 0;
}

Compilation message (stderr)

glo.cpp: In function 'int main()':
glo.cpp:17:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   17 |     scanf("%d %d", &n, &x);
      |     ~~~~~^~~~~~~~~~~~~~~~~
glo.cpp:19:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   19 |         scanf("%d", &a[i]);
      |         ~~~~~^~~~~~~~~~~~~

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 13
• Subtask 4: 0 / 10
• Subtask 5: 0 / 20
• Subtask 6: 0 / 17
• Subtask 7: 0 / 25