Submission #715183

#TimeUsernameProblemLanguageResultExecution timeMemory
715183NeltExamination (JOI19_examination)C++17
2 / 100
37 ms17432 KiB
#pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx,avx2,fma") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> /* DEFINES */ #define F first #define S second #define ll long long #define ull unsigned long long #define ld long double #define npos ULLONG_MAX #define INF LLONG_MAX #define vv(a) vector<a> #define pp(a, b) pair<a, b> #define pq(a) priority_queue<a> #define qq(a) queue<a> #define ss(a) set<a> #define mm(a, b) map<a, b> #define ump(a, b) unordered_map<a, b> #define sync \ ios_base::sync_with_stdio(0); \ cin.tie(0); \ cout.tie(0); #define elif else if #define endl "\n" #define allc(a) begin(a), end(a) #define all(a) a, a + sizeof(a) / sizeof(a[0]) #define pb push_back #define logi(a) __lg(a) #define sqrt(a) sqrtl(a) #define mpr make_pair #define ins insert using namespace std; using namespace __gnu_pbds; using namespace __cxx11; typedef char chr; typedef basic_string<chr> str; template <typename T, typename key = less<T>> using ordered_set = tree<T, null_type, key, rb_tree_tag, tree_order_statistics_node_update>; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); const ll MAX = 1e5 + 5; vv(ll) st[MAX << 1]; void build() { for (ll i = MAX; i < (MAX << 1); i++) sort(allc(st[i])); for (ll i = MAX - 1; i >= 1; i--) merge(allc(st[i << 1]), allc(st[i << 1 | 1]), st[i].begin()); } ll query(ll l, ll r, ll v) { ll ans = 0; for (l += MAX, r += MAX + 1; l < r; l >>= 1, r >>= 1) { if (l & 1) ans += st[l].size() - (lower_bound(allc(st[l]), v) - st[l].begin()), l++; if (r & 1) r--, ans += st[r].size() - (lower_bound(allc(st[r]), v) - st[r].begin()); } return ans; } void solve() { ll n, q; cin >> n >> q; pp(ll, ll) x[n]; for (auto &i : x) cin >> i.F >> i.S; sort(all(x)); if (n <= 3000 and q <= 3000) { while (q--) { ll a, b, c; cin >> a >> b >> c; ll ans = 0; for (ll i = 0; i < n; i++) ans += x[i].F >= a and x[i].S >= b and x[i].F + x[i].S >= c; cout << ans << endl; } } else { for (auto i : x) st[i.F + MAX].pb(i.S); build(); while (q--) { ll a, b, c; cin >> a >> b >> c; cout << query(a, MAX, c) << endl; } } } /* */ int main() { sync // precomp(); ll t = 1; // cin >> t; for (ll i = 1; i <= t; i++) // cout << "Case " << i << ": ", solve(); cerr << "\nTime elapsed : " << clock() * 1000.0 / CLOCKS_PER_SEC << " ms\n"; }
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