Submission #714678

#	Time	Username	Problem	Language	Result	Execution time	Memory
714678		Nelt	Plahte (COCI17_plahte)	C++17	0 / 160	2087 ms	479880 KiB

plahte

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx,avx2,fma")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

/* DEFINES */
#define F first
#define S second
#define ll long long
#define ull unsigned long long
#define ld long double
#define npos ULLONG_MAX
#define INF LLONG_MAX
#define vv(a) vector<a>
#define pp(a, b) pair<a, b>
#define pq(a) priority_queue<a>
#define qq(a) queue<a>
#define ss(a) set<a>
#define mm(a, b) map<a, b>
#define ump(a, b) unordered_map<a, b>
#define sync                      \
    ios_base::sync_with_stdio(0); \
    cin.tie(0);                   \
    cout.tie(0);
#define elif else if
#define endl "\n"
#define allc(a) begin(a), end(a)
#define all(a) a, a + sizeof(a) / sizeof(a[0])
#define pb push_back
#define logi(a) __lg(a)
#define sqrt(a) sqrtl(a)
#define mpr make_pair
#define ins insert
using namespace std;
using namespace __gnu_pbds;
using namespace __cxx11;
typedef char chr;
typedef basic_string<chr> str;
template <typename T, typename key = less<T>>
using ordered_set = tree<T, null_type, key, rb_tree_tag, tree_order_statistics_node_update>;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

void solve()
{
    ll n, m;
    cin >> n >> m;
    pp(pp(ll, ll), pp(ll, ll)) rect[n];
    for (auto &i : rect)
        cin >> i.F.F >> i.F.S >> i.S.F >> i.S.S;
    ss(ll) col[n];
    while (m--)
    {
        ll x, y, a;
        cin >> x >> y >> a;
        for (ll i = 0; i < n; i++)
            if ((rect[i].F.F <= x and rect[i].F.S <= y) and (x <= rect[i].S.F and y <= rect[i].S.S))
                col[i].ins(a);
    }
    for (auto &i : col)
        cout << i.size() << endl;
}
/*

*/
int main()
{
    sync
        // precomp();
        ll t = 1;
    // cin >> t;
    for (ll i = 1; i <= t; i++)
        // cout << "Case " << i << ": ",
        solve();
    cerr << "\nTime elapsed : " << clock() * 1000.0 / CLOCKS_PER_SEC << " ms\n";
}

• Subtask 1: 0 / 32
• Subtask 2: 0 / 32
• Subtask 3: 0 / 32
• Subtask 4: 0 / 32
• Subtask 5: 0 / 32