Submission #712604

#	Time	Username	Problem	Language	Result	Execution time	Memory
712604		jcelin	Dijamant (COI16_dijament)	C++14	0 / 100	2 ms	468 KiB

dijament

#include <bits/stdc++.h>
//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>

using namespace std;
//using namespace __gnu_pbds;

typedef long long ll;
typedef long double ld;

#define ii pair<int,int>
#define pll pair<ll,ll>
#define vi vector<int>
#define vii vector<ii>
#define vll vector<ll>
#define vpll vector<pll>
#define msi multiset<int>
#define si set<int>
#define PB push_back
#define PF push_front
#define PPB pop_back
#define PPF pop_front
#define X first
#define Y second
#define MP make_pair
#define FOR(i, a, b) for (int i = int(a); i < int(b); i++)
#define REP(i, n) FOR(i, 0, n)
#define all(x) (x).begin(), (x).end()

const int mod = 1e9 + 7;
const int MOD = 998244353;
const int inf = mod;
const ll INF = 1e18;
const int logo = 20;
const int MAXN = 1e3 + 100;
const int off = 1 << logo;
const int trsz = off << 1;

bitset<MAXN> cvis[MAXN][2];
bitset<MAXN> need[2];


vi g[MAXN], pg[MAXN], r[MAXN];
int nod = 1, pnod = 1, indeg[MAXN];
map<string, int> ids, pids;


void failalo(){
	FOR(i, 1, nod + 1){
		g[i].clear();
		for(auto x : pg[i]) g[i].PB(x);
		pg[i].clear();
		r[i].clear();	
		cvis[i][0].reset();
		cvis[i][1].reset();
		indeg[i] = 0;
	}	
	nod = pnod;
	ids.clear();
	for(auto &x : pids) ids[x.X] = x.Y;
	pids.clear();
	need[0].reset();
	need[1].reset();
}


bool check(){
	pids = ids;
	pnod = nod;
	FOR(i, 1, nod) pg[i] = g[i], indeg[i] = 0, r[i].clear(), cvis[i][0].reset(), cvis[i][1].reset();
	string s = "";
	while(s.empty()) getline(cin, s);
	
	string fir = "";
	for(auto &x : s){
		if(x == ' ') break;
		fir += x;
	}
	
	if(ids[fir]){
		failalo();
		return 0;
	}
	ids[fir] = nod++;
	vi sus; sus.clear();
	int nid = fir.size() + 3;
	while(nid < (int)s.size() - 1){
		string cur = "";
		while(s[nid] != ' ') cur += s[nid++];
		nid++;
		if(ids[cur]) sus.PB(ids[cur]);
		else{
			failalo();
			return 0;
		}
	}
	
	for(auto &x : sus) g[x].PB(ids[fir]);
	
	FOR(j, 1, nod) for(auto &x : g[j]) indeg[x]++, r[x].PB(j);
	
	vi topo, st; topo.clear(), st.clear();
	FOR(j, 1, nod) if(indeg[j] == 0) st.PB(j);
	while(!st.empty()){
		int u = st.back();
		st.PPB();
		topo.PB(u);
		for(auto &x : g[u]) if(--indeg[x] == 0) st.PB(x);
	}
	
	
	for(auto &x : topo){
		cvis[x][0][x] = 1;
		for(auto &y : g[x]) cvis[y][0] |= cvis[x][0];
	}
	reverse(all(topo));
	for(auto &x : topo){
		cvis[x][1][x] = 1;
		for(auto &y : r[x]) cvis[y][1] |= cvis[x][1];
	}
	
	FOR(j, 1, nod) FOR(i, 1, j){
		if(cvis[i][1][j] or cvis[i][0][j]) continue;
		need[0] = cvis[i][1] & cvis[j][1];
		need[1] = cvis[i][0] & cvis[j][0];
		need[0][i] = 0;
		need[0][j] = 0;
		need[1][i] = 0;
		need[1][j] = 0;
		if(need[0].count() and need[1].count()){
			failalo();
			return 0;
		}
	}
	
	return 1;
}

void solve(){
	int n;
	cin >> n;
	REP(i, n){
		if(check()) cout << "ok\n";
		else cout << "greska\n";
	}
}


int main(){
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
	cout.tie(NULL);
	int t=1;
	//cin >> t;
	while(t--)solve();
	return 0;
}

• Subtask 1: 0 / 13
• Subtask 2: 0 / 14
• Subtask 3: 0 / 29
• Subtask 4: 0 / 44