Submission #711814

#	Time	Username	Problem	Language	Result	Execution time	Memory
711814		tutis	Coins (LMIO19_monetos)	C++17	30.04 / 100	122 ms	3788 KiB

monetos

/*input
0 4 1 5
0 0 1 0
0 0 0 1
0 1 1 1
1 1 0 1
*/
#pragma GCC optimize("O3")
#pragma GCC target("avx2")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
using ll = long long;
using ull = unsigned long long;
using ld = long double;
template<typename A, typename B>
using omap = tree <A, B, less<A>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename A>
using oset = tree <A, null_type, less<A>, rb_tree_tag, tree_order_statistics_node_update>;
const ll mod = 1e9 + 7;
ll ran(ll a, ll b)
{
	//return a + (ll)(rng() % (b - a + 1));
	return uniform_int_distribution<ll>(a, b)(rng);
}
ll power(ll x, ll p)
{
	if (abs(x) >= mod)
		x %= mod;
	if (x < 0)
		x += mod;
	if (abs(p) >= mod - 1)
		p %= mod - 1;
	if (p < 0)
		p += mod - 1;
	ll r = 1;
	while (p)
	{
		if (p % 2)
			r = (r * x) % mod;
		x = (x * x) % mod;
		p /= 2;
	}
	return r;
}
void solve()
{
	int t, n, k1, k2;
	cin >> t >> n >> k1 >> k2;
	int a[n][n];
	int c = 0;
	for (int i = n - 1; i >= 0; i--)
	{
		for (int j = n - 1; j >= 0; j--)
		{
			cin >> a[i][j];
			c += a[i][j];
		}
	}
	int sp[n][n + 1];
	for (int i = 0; i < n; i++)
	{
		sp[i][0] = 0;
		for (int j = 0; j < n; j++)
			sp[i][j + 1] = sp[i][j] + a[i][j];
	}
	int x[n + 2];
	int* h = x + 1;
	h[-1] = n;
	h[n] = 0;
	{
		int c1 = c;
		for (int i = 0; i < n; i++)
		{
			h[i] = min(n, c1);
			c1 -= h[i];
		}
	}
	int D = 5;
	int S = 50;
	int te = 10;
	if (n <= 50)
	{
		D = 20;
		S = 100;
		te = 5;
	}
	pair<int, int> dp[n][2 * D + 1][2 * S + 1];
	for (int t = 0; t < te; t++)
	{
		for (int i = 0; i < n; i++)
			for (int d = -D; d <= D; d++)
				for (int s = -S; s <= S; s++)
					dp[i][d + D][s + S] = { -1e8, -1};
		for (int i = 0; i < n; i++)
		{
			for (int d = -D; d <= D; d++)
			{
				int hi = h[i] + d;
				if (hi < 0 || hi > n)
					continue;
				if (i == 0)
				{
					dp[i][d + D][d + S] = {sp[i][hi], 0};
				}
				else
				{
					for (int dj = -D; dj <= D; dj++)
					{
						if (h[i - 1] + dj >= hi)
						{
							for (int s = -S; s <= S; s++)
							{
								int sj = s - d;
								if (sj >= -S && sj <= S)
								{
									dp[i][d + D][s + S] = max(dp[i][d + D][s + S], {dp[i - 1][dj + D][sj + S].first + sp[i][hi], dj});
								}
							}
						}
					}
				}
			}
		}
		int s = 0;
		int i = n - 1;
		int di = 0;
		{
			pair<int, int>mx = { -1000, -1000};
			for (int d = -D; d <= D; d++)
				mx = max(mx, {dp[i][d + D][s + S].first, d});
			di = mx.second;
		}
		while (i >= 0)
		{
			h[i] += di;
			int dj = dp[i][di + D][s + S].second;
			s -= di;
			i--;
			di = dj;
		}
	}
	for (int i = 0; i < n; i++)
		for (int j = 0; j < n; j++)
			a[i][j] = 0;
	for (int i = 0; i < n; i++)
		for (int j = 0; j < h[i]; j++)
			a[i][j] = 1;
	for (int i = n - 1; i >= 0; i--)
	{
		for (int j = n - 1; j >= 0; j--)
		{
			cout << a[i][j] << " ";
		}
		cout << "\n";
	}
}
int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	solve();
}

• Subtask 1: 30.035133365909996 / 100