Submission #709487

#	Time	Username	Problem	Language	Result	Execution time	Memory
709487		urosk	Jail (JOI22_jail)	C++14	49 / 100	5094 ms	454540 KiB

jail

#define here cerr<<"===========================================\n"
#define dbg(x) cerr<<#x<<": "<<x<<endl;
#include "bits/stdc++.h"
//#include <ext/pb_ds/tree_policy.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
#define ld double
#define ll int
#define llinf 100000000000000000LL // 10^17
#define pb push_back
#define popb pop_back
#define fi first
#define sc second
#define endl '\n'
#define pll pair<ll,ll>
#define pld pair<ld,ld>
#define all(a) a.begin(),a.end()
#define ceri(a,l,r) {cerr<<#a<<": ";for(ll i_ = l;i_<=r;i_++) cerr<<a[i_]<< " ";cerr<<endl;}
#define cer(a) {cerr<<#a<<": ";for(ll x_ : a) cerr<<x_<< " ";cerr<<endl;}

#define daj_mi_malo_vremena ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);

using namespace std;
//using namespace __gnu_pbds;
/*
ll add(ll x,ll y){
    x+=y;
    if(x<0){
        x%=mod;
        x+=mod;
    }else{
        if(x>=mod) x%=mod;
    }
    return x;
}
ll mul(ll a,ll b){
	ll ans = (a*b)%mod;
	if(ans<0) ans+=mod;
	return ans;
}
typedef tree<int,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
typedef tree<int,null_type,less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_multiset;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll rnd(ll l,ll r){
    return uniform_int_distribution<ll>(l,r)(rng);
}
*/
#define maxn 3000005
#define lg 22
ll n,m;
vector<ll> g[maxn];
vector<ll> v[maxn];
ll tsz = 0;
ll id[maxn][lg][2];
ll st[maxn][lg];
ll in[maxn],out[maxn],ti = 0;
bool intree(ll x,ll y){return in[y]<=in[x]&&out[x]<=out[y];}
ll lca(ll x,ll y){
    if(intree(x,y)) return y;
    if(intree(y,x)) return x;
    for(ll j = lg-1;j>=0;j--){
        if(!intree(x,st[y][j])) y = st[y][j];
    }
    return st[y][0];
}
void dfs(ll u,ll p){
    in[u] = ++ti;
    st[u][0] = p;
    for(ll s : g[u]) if(s!=p) dfs(s,u);
    out[u] = ti-1;
}
ll get(ll x,ll y){
    for(ll j = lg-1;j>=0;j--){
        if(!intree(y,st[x][j])) x = st[x][j];
    }
    return x;
}
void add(ll x,ll y,bool smer,ll nod){
    for(ll j = lg-1;j>=0;j--){
        if(!intree(y,st[x][j])){
            if(smer) v[id[x][j][1]].pb(nod);
            else v[nod].pb(id[x][j][0]);
            x = st[x][j];
        }
    }
    if(smer) v[id[x][0][1]].pb(nod);
    else v[nod].pb(id[x][0][0]);
    if(smer) v[id[y][0][1]].pb(nod);
    else v[nod].pb(id[y][0][0]);
}
ll deg[maxn];
void tc(){
    ti = 0;
    cin >> n;
    for(ll i = 1;i<=n-1;i++){
        ll x,y; cin >> x >> y;
        g[x].pb(y);
        g[y].pb(x);
    }
    dfs(1,1);
    for(ll i = 1;i<=n;i++) id[i][0][0] = i,id[i][0][1] = i+n;
    tsz = 2*n;
    for(ll j = 1;j<lg;j++) for(ll i = 1;i<=n;i++){
        st[i][j] = st[st[i][j-1]][j-1];
        ++tsz;
        if(tsz>=maxn){
            while(1) here;
        }
        id[i][j][0] = tsz;
        v[tsz].pb(id[i][j-1][0]);
        v[tsz].pb(id[st[i][j-1]][j-1][0]);
        ++tsz;
        if(tsz>=maxn){
            while(1) here;
        }
        id[i][j][1] = tsz;
        v[id[i][j-1][1]].pb(tsz);
        v[id[st[i][j-1]][j-1][1]].pb(tsz);
    }
    cin >> m;
    for(ll i = 1;i<=m;i++){
        ll x,y; cin >> x >> y;
        ++tsz;
        if(tsz>=maxn){
            while(1) here;
        }
        v[x].pb(tsz);
        v[tsz].pb(n+y);
        ll z = lca(x,y);
        if(z!=x){
            add(x,get(x,z),1,tsz);
            add(st[x][0],z,0,tsz);
        }
        if(z!=y){
            add(y,get(y,z),0,tsz);
            add(st[y][0],z,1,tsz);
        }
    }
    queue<ll> q;
    for(ll i = 1;i<=tsz;i++) deg[i] = 0;
    for(ll i = 1;i<=tsz;i++){
        for(ll j : v[i]) deg[j]++;
    }
    for(ll i = 1;i<=tsz;i++){
        if(!deg[i]) q.push(i);
    }
    ll cnt = 0;
    while(q.size()){
        ll x = q.front();
        q.pop();
        cnt++;
        for(ll y : v[x]){
            deg[y]--;
            if(!deg[y]) q.push(y);
        }
    }
    if(cnt!=tsz) cout<<"No"<<endl;
    else cout<<"Yes"<<endl;
    for(ll i = 1;i<=n;i++) g[i].clear();
    for(ll i = 1;i<=tsz;i++) v[i].clear();
}
int main(){
	daj_mi_malo_vremena
    int t; t = 1;
    cin >> t;
    while(t--){
        tc();
    }
	return 0;
}
/**
1
8
1 2
2 3
3 4
4 5
5 6
6 7
7 8
2
3 4
4 8

2
7
1 2
2 3
3 4
4 5
3 6
6 7
2
4 1
5 7
4
1 2
1 3
1 4
3
2 3
3 4
4 2

3
3
1 2
2 3
2
2 1
3 2
7
1 2
2 3
3 4
4 5
5 6
6 7
3
1 3
4 2
2 5
8
1 2
2 3
3 4
4 5
5 6
6 7
7 8
4
1 5
2 6
3 7
4 8
**/

• Subtask 1: 0 / 5
• Subtask 2: 5 / 5
• Subtask 3: 16 / 16
• Subtask 4: 28 / 28
• Subtask 5: 0 / 12
• Subtask 6: 0 / 11
• Subtask 7: 0 / 23