Submission #709395

#	Time	Username	Problem	Language	Result	Execution time	Memory
709395		jiahng	Financial Report (JOI21_financial)	C++14	48 / 100	132 ms	16600 KiB

Main

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
#define int ll
typedef pair<int,int> pi;
typedef vector <int> vi;
typedef vector <pi> vpi;
typedef pair<pi, ll> pii;
typedef set <ll> si;
typedef long double ld;
#define f first
#define s second
#define mp make_pair
#define FOR(i,s,e) for(int i=s;i<=int(e);++i)
#define DEC(i,s,e) for(int i=s;i>=int(e);--i)
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define lbd(x, y) lower_bound(all(x), y)
#define ubd(x, y) upper_bound(all(x), y)
#define aFOR(i,x) for (auto i: x)
#define mem(x,i) memset(x,i,sizeof x)
#define fast ios_base::sync_with_stdio(false),cin.tie(0),cout.tie(0)
#define maxn 200010
#define INF (ll)1e18
typedef pair <vi, int> pvi;
typedef pair <int,pi> ipi;
typedef vector <pii> vpii;
#define DEBUG 0
#define MOD 1000003233

int TC;
int N,M,D;
int A[maxn],nxt[maxn],sz[maxn];
vi B[maxn];
bool inc[maxn];
int p[maxn],dp[maxn];
int fl(int x){
    if (p[x] == x) return x;
    return p[x] = fl(p[x]);
}
void join(int a,int b){
    a = fl(a); b = fl(b);
    if (a == b) return;
    p[a] = b;
    sz[b] += sz[a];
}
void solve(){
    cin >> N >> D;
    vi tmp;
    FOR(i,1,N){
        cin >> A[i]; tmp.pb(A[i]);
    }
    sort(all(tmp));
    FOR(i,1,N) A[i] = lower_bound(all(tmp), A[i]) - tmp.begin() + 1;

    FOR(i,1,N) B[A[i]].pb(i);
    FOR(i,1,N) p[i] = i,sz[i] = 1;

    set <int> st;
    DEC(i,N,1){
        aFOR(j, B[i]){
            auto it = st.upper_bound(j);
            if (it == st.end()) nxt[j] = N;
            else nxt[j] = *it - 1;
        }

        aFOR(j, B[i]){
            inc[j] = 1;
            if (inc[j-1]) join(j,j-1);
            if (inc[j+1]) join(j+1,j);

            int x = fl(j); //assert(fl(x-1) != x);
            if (sz[x] >= D) st.insert(x);
        }

    }

    dp[N] = 0;
    DEC(i,N-1,1){
        dp[i] = 0;
        FOR(j,i+1,nxt[i]+D) if (A[j] > A[i]) dp[i] = max(dp[i], dp[j] + 1);
    }
    //FOR(i,1,N) cout << dp[i] << ' ';
    //cout << '\n';
    cout << *max_element(dp+1,dp+N+1)+1;


}
int32_t main(){
    fast;
    solve();
    //cin >> TC;
    //while (TC--) solve();

}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 0 / 12
• Subtask 5: 0 / 5
• Subtask 6: 0 / 35