Submission #709389

#TimeUsernameProblemLanguageResultExecution timeMemory
709389JohannExamination (JOI19_examination)C++14
2 / 100
3028 ms9920 KiB
// TODO: Still to solve... #include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair<ll, ll> pii; typedef vector<ll> vi; typedef vector<pii> vpii; typedef vector<vpii> vvpii; #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() struct Req { ll a, b, c; int idx; }; struct SqrtDecom { vpii newStuff; vpii stuff; vvpii buckets; vi minele; int sq; void init(int N) { sq = ceil(sqrt(N)); } void insert(pii &item) { newStuff.push_back(item); if (sz(newStuff) == sq) { for (pii tmp : newStuff) stuff.push_back(tmp); sort(all(stuff)); newStuff.clear(); buckets.push_back(vpii(sq)); minele.push_back(0); for (int i = 0; i < sz(stuff); ++i) buckets[i / sq][i % sq] = stuff[i]; for (int i = 0; i < sz(buckets); ++i) { minele[i] = buckets[i].front().first; sort(all(buckets[i]), [&](pii &a, pii &b) { return a.second < b.second; }); } } } int answer(Req &q) { int ans = 0; for (pii r : newStuff) if (r.first >= q.a && r.second >= q.b) ++ans; int idx = sz(buckets) - 1; while (idx >= 0 && minele[idx] >= q.a) { ans += buckets[idx].end() - lower_bound(all(buckets[idx]), make_pair(0LL, q.b), [&](const pii a, const pii b) { return a.second < b.second; }); idx--; } if (idx != -1) for (pii r : buckets[idx]) if (r.first >= q.a && r.second >= q.b) ++ans; return ans; } }; int main() { ios::sync_with_stdio(false); cin.tie(0); int N, Q; cin >> N >> Q; vpii ST(N); // A <= S[i] , B <= T[i], C <= S[i] + T[i] for (int i = 0; i < N; ++i) cin >> ST[i].first >> ST[i].second; vector<Req> Queries(Q); for (int i = 0, a, b, c; i < Q; ++i) { cin >> a >> b >> c; Queries[i] = {a, b, c, i}; } vi ans(Q); sort(all(Queries), [&](Req &a, Req &b) { return a.c > b.c; }); sort(all(ST), [&](pii &a, pii &b) { return a.first + a.second > b.first + b.second; }); SqrtDecom sqd; sqd.init(N); int idx = 0; for (int i = 0; i < sz(Queries); ++i) { while (idx < sz(ST) && ST[idx].first + ST[idx].second >= Queries[i].c) { sqd.insert(ST[idx]); ++idx; } ans[Queries[i].idx] = sqd.answer(Queries[i]); } for (int x : ans) cout << x << "\n"; return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...